Choose a Lesson

Interactive GCSE lessons. Each includes explanations, worked examples, a live calculator, and practice questions.

Geometry & Measures

Properties of Shapes

Polygons, angles, symmetry, circles, and 3D shapes with Euler's formula.

Foundation & HigherStart →
Statistics

Pie Charts

Draw, read, and interpret pie charts. Interactive builder included.

Foundation & HigherStart →
🍳
Ratio & Proportion

Direct Proportion

y = kx with food examples and a live recipe scaler. Drag a slider to scale any recipe.

Foundation & HigherStart →
½
Number

Fractions, Decimals & Percentages

Convert between F, D and P with an interactive converter and bar model.

Foundation & HigherStart →
%
Number

Percentages (Calculator)

Multipliers, % increase/decrease, reverse percentages — all with a live number-line calculator.

Foundation & HigherStart →
🌆
Ratio & Proportion

Best Buys

Compare value for money using unit rates. Which deal gives the most for your money?

Foundation & HigherStart →
nᵗʰ
Algebra

Nth Term

Find and use nth term formulas for arithmetic and quadratic sequences.

Foundation & HigherStart →
🗺
Ratio, Proportion & Rates

Scales, Maps & Units

Map scales, unit conversions, metric and imperial — with an interactive converter.

Foundation & HigherStart →
🚗
Ratio, Proportion & Rates

Speed, Distance & Time

The SDT triangle, average speed, and time unit conversions — with a live calculator.

Foundation & HigherStart →
Ratio, Proportion & Rates

Ratio & Fractions

Simplify ratios, share in a given ratio, link ratios to fractions — interactive splitter included.

Foundation & HigherStart →
~
Number

Multiplying, Dividing & Estimating

Long multiplication, division, rounding, significant figures and estimation techniques.

Foundation & HigherStart →
💲
Ratio, Proportion & Rates

Exchange Rates, Ratio & Percentages

Currency conversions combined with ratio and percentage problems.

Foundation & HigherStart →
Algebra

Powers, Roots & Index Laws

Squares, cubes, index notation and the six index laws — with an interactive calculator.

Foundation & HigherStart →
𝑥
Algebra

Algebra, Substitution & Factorising

Expressions, substitution, expanding brackets and factorising — step by step.

Foundation & HigherStart →
Geometry & Measures

Area & Perimeter

Rectangles, triangles, parallelograms, trapeziums and composite shapes — with a live calculator.

Foundation & HigherStart →
Algebra

Function Machines

Inputs, outputs, inverse functions and composite function machines — interactive builder.

Foundation & HigherStart →
Geometry & Measures

Circles, Surface Area & Volume

Arc length, sector area, cylinder, cone and sphere — with a full 3D calculator.

Foundation & HigherStart →
Geometry & Measures

Vectors

Column vectors, adding and subtracting, scalar multiplication and magnitude.

Foundation & HigherStart →
📈
Statistics

Graphs & Charts

Bar charts, line graphs, pictograms, frequency polygons and scatter graphs with correlation.

Foundation & HigherStart →
μ
Statistics

Averages & Range

Mean, median, mode and range from lists, tables and grouped data — with a live calculator.

Foundation & HigherStart →
📊
Statistics

Frequency Tables

Tally charts, ungrouped and grouped tables, mean from fx, two-way tables and probability.

Foundation & HigherStart →
🎲
Probability

Probability

Experiments, theoretical probability, expected outcomes, mutually exclusive and independent events.

Foundation & HigherStart →
📋
Statistics

Handling Data

Sampling methods, organising and representing data, averages, spread and comparing distributions.

Foundation & HigherStart →
Geometry & Measures

Working in 2D: Transformations

Reflection, rotation, translation and enlargement — with scale factors and centres.

Foundation & HigherStart →
📐
Number

Measures & Accuracy

Estimation, approximation, calculator methods, bounds and error intervals.

Foundation & HigherStart →
x
Algebra

Equations & Inequalities

Linear equations, quadratics, simultaneous equations and inequalities on number lines.

Foundation & HigherStart →
Geometry & Measures

Circles, Constructions & Loci

Circle theorems, geometric constructions with compass and ruler, and loci problems.

Foundation & HigherStart →
📈
Algebra

Graphs: Straight Lines & Kinematics

y=mx+c, parallel and perpendicular lines, distance-time and velocity-time graphs.

Foundation & HigherStart →
Algebra

Sequences: Special & Geometric

Arithmetic, geometric, Fibonacci, triangular and square sequences with nth term.

Foundation & HigherStart →
Geometry & Measures

Pythagoras & Trigonometry

Pythagoras, SOHCAHTOA, exact values, sine and cosine rules, and 3D trig.

Foundation & HigherStart →
×10
Number

Calculations 2: Standard Form & Surds

Standard form, exact calculations, surds and rationalising the denominator.

Foundation & HigherStart →
Algebra

Graphs 2: Quadratics & Real-Life

Quadratic graphs, completing the square, graph families and real-life interpretation.

Foundation & HigherStart →
🌳
Probability

Combined Events

Sample spaces, possibility diagrams, tree diagrams and conditional probability.

Foundation & HigherStart →
f(x)
Algebra

Formulae & Functions

Substitution, rearranging formulae, identities and composite functions.

Foundation & HigherStart →
📊
Statistics

Handling Data 2

Cumulative frequency, box plots, histograms, time series and scatter graphs.

Foundation & HigherStart →
Number

Units & Proportionality

Compound units, direct and inverse proportion, growth and decay.

Foundation & HigherStart →
Probability & Sets

Venn Diagrams

Sets, union, intersection, complement — with an interactive two and three-circle builder.

Foundation & HigherStart →

Learning Objectives

Tick each off as you go.

Where this fits

Geometry and Measures — both Foundation and Higher papers. Properties must be recalled without prompting and applied to unseen diagrams. They are rarely on the formula sheet.

Polygons

A polygon is a closed 2D shape with straight sides.

Equilateral Triangle

  • 3 equal sides
  • All angles 60°
  • 3 lines of symmetry
  • Rotational order 3

Isosceles Triangle

  • 2 equal sides
  • 2 equal base angles
  • 1 line of symmetry
  • No rotational symmetry

Square

  • 4 equal sides, all 90°
  • 4 lines of symmetry
  • Rotational order 4

Rectangle

  • Opposite sides equal, 90°
  • 2 lines of symmetry
  • Rotational order 2

Rhombus

  • 4 equal sides
  • Opposite angles equal
  • 2 lines of symmetry
  • Rotational order 2

Trapezium

  • One pair of parallel sides
  • Co-interior angles = 180°
  • No rotational symmetry

Regular Pentagon

  • Interior angle 108°
  • 5 lines of symmetry
  • Rotational order 5

Regular Hexagon

  • Interior angle 120°
  • 6 lines of symmetry
  • Rotational order 6

Quadrilaterals

All quadrilaterals: interior angles sum to 360°. A square is a special rectangle. A rhombus is a special parallelogram.

  • Parallelogram: opposite sides equal and parallel, no lines of symmetry, order 2
  • Kite: two pairs of adjacent equal sides, 1 line of symmetry, order 1
  • Isosceles Trapezium: equal legs, 1 line of symmetry

Angles in Polygons

Interior and exterior angles follow fixed rules for all polygons.

Acute0–90°Less than a right angle
Right90°Square corner
Obtuse90–180°Between right and straight
Reflex180–360°Greater than straight

Interior Angle Sum

FormulaInterior sum = (n − 2) × 180°
  • Triangle: 180°
  • Quadrilateral: 360°
  • Pentagon: 540°
  • Hexagon: 720°
  • Octagon: 1080°

Each Interior Angle — Regular Polygon

FormulaEach angle = (n − 2) × 180° ÷ n

Hexagon: (6−2)×180÷6 = 120°

Exterior Angles

Key factExterior angles always sum to 360°. Each = 360 ÷ n

Interior + Exterior = 180°

Angle Rules

  • Angles on a straight line = 180°
  • Angles around a point = 360°
  • Vertically opposite angles are equal
  • Alternate angles equal (Z, parallel lines)
  • Co-interior angles = 180° (C, parallel lines)
  • Corresponding angles equal (F, parallel lines)

Symmetry

Two types appear in GCSE. Know both for every common shape.

Line Symmetry

  • Equilateral triangle: 3
  • Isosceles triangle: 1
  • Square: 4
  • Rectangle: 2
  • Rhombus: 2
  • Parallelogram: 0
  • Regular hexagon: 6
  • Circle: infinite

Rotational Symmetry — Order

  • Square: 4
  • Rectangle: 2
  • Rhombus: 2
  • Parallelogram: 2
  • Equilateral triangle: 3
  • Regular pentagon: 5
  • Regular hexagon: 6
  • Kite / Isosceles triangle: 1 (none)

Regular polygon with n sides: lines of symmetry = n, rotational order = n. These values always match for regular polygons.

Circles

Know every term and how it links to the others.

Vocabulary

  • Radius — centre to circumference
  • Diameter — chord through centre, d = 2r
  • Circumference — perimeter, C = πd = 2πr
  • Chord — line joining two circumference points
  • Tangent — touches circumference at exactly one point
  • Arc — section of circumference
  • Sector — two radii and an arc (pizza slice)
  • Segment — chord and arc

A tangent is always perpendicular to the radius at the point of contact. Mark this 90° on any diagram immediately.

Formulas

CircumferenceC = πd = 2πr
AreaA = πr²

Both are on the formula sheet. Know how to apply them and work backwards.

3D Shapes

Every polyhedron satisfies Euler's formula.

Euler's Formula

For any polyhedronF + V − E = 2

Use to find a missing value when two of the three are known.

Common Shapes

  • Cube: 6F, 12E, 8V
  • Cuboid: 6F, 12E, 8V
  • Triangular prism: 5F, 9E, 6V
  • Square pyramid: 5F, 8E, 5V
  • Tetrahedron: 4F, 6E, 4V
  • Cylinder: 3F (1 curved), 2E, 0V
  • Cone: 2F (1 curved), 1E, 1V
  • Sphere: 1F, 0E, 0V

Nets

A net folds to make a 3D shape. A cube has 11 valid nets. Check all faces are present and correctly positioned before confirming a net is valid.

Practice

Select the correct answer.

Q1 — Exterior angles

A regular polygon has an exterior angle of 45°. How many sides?

Q2 — Symmetry

Which quadrilateral has exactly one line of symmetry?

Q3 — Interior angles

Sum of interior angles of a pentagon?

Q4 — 3D shapes

A triangular prism has how many edges?

Exam Tips

The most common errors in this topic.

01

Use (n−2)×180 every time

Do not try to memorise each polygon's sum. One formula works for all cases.

02

Exterior angles always sum to 360°

360 ÷ exterior angle = number of sides for any regular polygon.

03

Tangent meets radius at 90°

Mark this right angle immediately on any circle diagram. It unlocks most circle problems.

04

Give reasons for every angle

Write the rule name alongside your working. Missing reasons lose marks on reasoning questions.

05

Verify 3D shapes with F + V − E = 2

If given values do not satisfy Euler's formula, something is wrong.

Congruence

Two shapes are congruent if they are exactly the same shape and size. One may be reflected, rotated or translated — but not scaled.

Four conditions for congruent triangles

ConditionWhat it meansSufficient?
SSSThree sides equalYes ✓
SASTwo sides and the included angle equalYes ✓
ASA / AASTwo angles and a corresponding side equalYes ✓
RHSRight angle, hypotenuse and one side equalYes ✓
SSATwo sides and a non-included angleNo ✗ (ambiguous)
AAAThree angles equalNo ✗ (only similar)

Proving congruence in exam questions

1

Identify which condition applies

Look at what information is given — sides, angles, right angles.

2

State three pieces of matching information

Write each one with a reason (e.g. "AB = DE — given", "angle B = angle E — vertically opposite").

3

State the congruence condition

Conclude: "Therefore triangles ABC and DEF are congruent (SAS)" or whichever condition applies.

Congruent shapes have equal areas. Corresponding sides and angles are equal. Always match vertices in the correct order: triangle ABC ≅ triangle DEF means A↔D, B↔E, C↔F.

Similarity

Two shapes are similar if they have the same angles and their corresponding sides are in the same ratio (scale factor).

Finding the scale factor

Linear scale factork = corresponding side in larger shape ÷ corresponding side in smaller shape
Area scale factor=
Volume scale factor=

Worked example

Two similar triangles. Smaller has sides 3, 4, 5 cm. Larger has longest side 10 cm.

Scale factor k10 ÷ 5 = 2
Other sides of larger triangle3×2 = 6 cm   4×2 = 8 cm
Area scale factork² = 4. If smaller area = 6 cm², larger area = 6×4 = 24 cm²

Proving similarity

  • Show all three angles are equal (AA is sufficient for triangles — the third follows automatically)
  • Show all corresponding sides are in the same ratio (SSS similarity)
  • Show two sides in ratio and included angle equal (SAS similarity)
Area and volume do not scale linearly. If the linear scale factor is 3, areas are 9× bigger and volumes are 27× bigger. A very common exam error is multiplying areas by k instead of k².

Learning Objectives

Tick each off as you go.

Where this fits

Statistics strand, Foundation and Higher. Questions range from angle calculations to comparing two charts with different sample sizes.

What is a Pie Chart?

A circle divided into sectors. Each sector's size is proportional to its frequency.

Key Vocabulary

  • Sector — a slice representing one category
  • Angle — at the centre; all must sum to 360°
  • Frequency — count for each category
  • Proportion — frequency ÷ total
Most important fact: All sectors must sum to 360° because a full circle = 360° = 100% of the data.

Core Formulas

Drawing — angle for each sectorAngle = (frequency ÷ total) × 360°
Reading — frequency from angleFrequency = (angle ÷ 360) × total

Drawing Pie Charts

Follow these six steps every time.

1

Find the total frequency

Add all frequencies. Write it down before calculating anything else.

2

Calculate each angle

(frequency ÷ total) × 360. Round to nearest degree.

3

Check angles sum to 360°

If 359° or 361°, adjust the largest sector by 1°.

4

Draw circle and starting radius

Draw a radius from centre to 12 o'clock. This is your baseline.

5

Measure and draw each sector

Place protractor at centre along the current radius. Mark the angle. Draw a new radius. That new radius is the baseline for the next sector.

6

Label every sector and add a title

Category name + angle or percentage. Missing labels cost marks.

Common error: Measuring each angle from 12 o'clock instead of from the previous sector's edge. Every new sector starts where the last one ended.

Interactive Builder

Add or remove data points — angles calculate automatically and the chart updates live.

Pie Chart Builder

Edit labels and frequencies — chart updates instantly

Frequencies
Total0
Angles sum
Try: Set values to 12, 8, 6, 4 (total = 30). Angles = 144°, 96°, 72°, 48°. Add a new category and watch the chart update. Min 2, max 8 categories.

Reading Pie Charts

Always use the formula — never read the angle directly as the frequency.

Frequency from angle

FormulaFrequency = (angle ÷ 360) × total

Example: 48 students, sector 90°. → (90÷360)×48 = 12 students

Percentage from angle

FormulaPercentage = (angle ÷ 360) × 100

Example: 72° → (72÷360)×100 = 20%

Missing angle

FormulaMissing = 360 − (sum of other angles)
120° 90° 72° 78°

Favourite Sports — 60 students

Football120°→20
Swimming90°→15
Tennis72°→12
Other78°→13

Worked Examples

Try each calculation before reading the answer.

Example 1 — Drawing from a table

30 students asked about travel to school.

TransportFrequencyCalculationAngle
Car12(12÷30)×360144°
Bus8(8÷30)×36096°
Walk6(6÷30)×36072°
Cycle4(4÷30)×36048°
Total30360°
Check: 144+96+72+48 = 360. Verified before drawing.

Example 2 — Reading

72 people surveyed. Coffee sector = 135°. How many chose coffee?

Apply formulaFrequency = (135÷360)×72 = 0.375×72 = 27
27 people. Show full working — method marks count.

Example 3 — Missing angle

Four sectors. Known angles: 85°, 110°, 95°. Find the fourth.

Subtract from 360Missing = 360−(85+110+95) = 360−290 = 70°

Practice

Select the correct answer.

Q1 — Angle calculation

40 people surveyed. 10 chose bananas. What is the sector angle?

Q2 — Reading

120 students surveyed. Science sector = 60°. How many chose Science?

Q3 — Missing angle

Three known sectors: 95°, 115°, 80°. Find the fourth.

Q4 — Comparing charts (Higher)

Chart A: 80 students. Chart B: 120 students. Drama sector = 90° in both. Which has more Drama students, by how many?

Exam Tips

The most common mistakes in this topic.

01

Verify angles sum to 360° before drawing

Add all angles first. Fix errors before touching a compass.

02

Measure from the previous edge

Each new sector starts where the previous ended, not from 12 o'clock.

03

Show full working

Write (freq÷total)×360 in full. Method marks apply even when wrong.

04

Label every sector

Name + angle or percentage. Missing labels = free marks lost.

05

Use formula, not angle, for frequency

Frequency = (angle÷360)×total. The angle shows proportion, not count.

06

Different totals = different scales

Same angle in two charts does not mean same count. Calculate separately.

Learning Objectives

Tick each off as you go.

Where this fits

Ratio, Proportion and Rates of Change — Foundation and Higher. Foundation: find k and a missing value. Higher: form equations, use y ∝ x², y ∝ √x, inverse proportion.

What is Direct Proportion?

When one quantity increases, the other increases at the same rate. When one doubles, the other doubles.

A food example

A cookie recipe uses 200g of butter to make 20 cookies.

  • 10 cookies → 100g butter (halved)
  • 40 cookies → 400g butter (doubled)
  • 60 cookies → 600g butter (tripled)

The ratio butter ÷ cookies = 10g per cookie every time. That ratio is the constant k.

The key test

Divide y by x for every pair. If the answer is always the same, the relationship is directly proportional. That number is k.

Cookies (x)Butter in g (y)y ÷ xConclusion
1010010k = 10
2020010k = 10
3535010k = 10
AnyAny10 alwaysDirectly proportional ✓
Direct proportion: y ÷ x = constant (k). The graph is a straight line through the origin (0, 0).

The Formula

Every direct proportion relationship can be written as y = kx.

y = kx

Formulay = kx    k = constant of proportionality
Finding kk = y ÷ x    (use any known pair)

Three-step method — always use this

1

Find k from a known pair

Substitute one known (x, y) into y = kx and solve for k.

2

Write the equation

Write y = kx with your value of k. This is the complete equation.

3

Substitute and solve

Put the new x or y in and calculate the unknown.

Doughnut example

40 doughnuts require 625g of flour. How much flour for 64 doughnuts?

Step 1 — find k (g per doughnut)k = 625 ÷ 40 = 15.625 g per doughnut
Step 2 — write equationFlour = 15.625 × doughnuts
Step 3 — substitute 64 doughnutsFlour = 15.625 × 64 = 1000g = 1 kg
Answer: 1000g of flour for 64 doughnuts.

Recipe Scaler

This tool uses direct proportion. Change the number of portions and every ingredient scales automatically.

🍳 Doughnut Proportion Scaler

Uses y = kx · Base: 40 doughnuts

140200
Results
625g
How this works: We know the base amount (40 doughnuts = base flour). The calculator finds k = base flour ÷ 40, then multiplies by your chosen quantity. This is y = kx in action.

🍼 Full Recipe Scaler — Chocolate Cake

Base recipe serves 8 — drag to scale

1840
IngredientFor 8For 8
k = servings ÷ 8 = 1.00  ·  All ingredients × 1.00
Direct proportion in action: every ingredient is multiplied by the same ratio (new servings ÷ original servings). That ratio is k. The equation for each ingredient is: new amount = k × original amount.

Direct Proportion Calculator

Step 1: enter a pair of values you already know. Step 2: enter the new value you want to find. The calculator does the rest.

How to use this calculator

Direct proportion always follows y = kx. To use this tool:

  • Known pair — enter two values you already know (e.g. 40 doughnuts needs 625g flour)
  • Find y — enter a new x to calculate the matching y (e.g. how much flour for 70 doughnuts?)
  • Find x — enter a new y to work backwards and find x (e.g. how many doughnuts for 1000g of flour?)

y = kx Calculator

Enter your known values — the calculator finds k and solves

Step 1 — What you already know

Step 2 — What you want to find

Waiting for values
Enter an x and y pair on the left to begin.
Remember: k = y ÷ x (always divide)
To find y: multiply k × x
To find x: divide y ÷ k

Graphs of Direct Proportion

The graph of y = kx is always a straight line through the origin. The gradient equals k.

Key features

  • Straight line — the relationship is linear
  • Passes through origin (0, 0) — when x = 0, y = 0
  • Gradient = k (steeper line = larger k)
  • If the line does not pass through the origin: not direct proportion

Reading k from a graph

Gradientk = rise ÷ run = change in y ÷ change in x

Pick two clear points. Divide change in y by change in x. That is k. Write y = kx.

Table check

If y ÷ x is constant in every row, the relationship is directly proportional.

xyy ÷ x
263
5153
10303 — directly proportional, k=3
y = mx + c with c ≠ 0 is NOT direct proportion. The line must pass through (0, 0).

Practice

Select the correct answer.

Q1 — Finding k

y ∝ x. When x = 5, y = 30. What is k?

Q2 — Food context

A recipe uses 200g of flour for 8 muffins. How much flour for 14 muffins?

Q3 — Finding x

y = kx. When x = 3, y = 21. Find x when y = 49.

Q4 — Identify direct proportion

Which table shows direct proportion?

Exam Tips

The most common mistakes.

01

Always find k first

Do not scale informally. k = y ÷ x, then write y = kx.

02

Write y ∝ x then y = kx

The ∝ step earns a method mark in many mark schemes.

03

Graph must pass through origin

If it does not, it is not direct proportion. State this clearly.

04

To find x from y: divide by k

x = y ÷ k. Multiplying gives the wrong answer.

05

Check tables: y ÷ x must be constant

Show this check in working. One calculation per row.

06

y = mx + c (c ≠ 0) is not direct proportion

The line must cross the y-axis at zero.

Learning Objectives

Tick each off as you go.

Where this fits

Number strand, non-calculator paper. Common equivalences must be memorised. Converting between forms is tested directly and also appears inside other topics like probability, ratio, and percentage questions.

What is FDP?

Three different ways to write the same value. They are equivalent — they describe the same portion of a whole.

The three forms — using pizza!

Imagine a pizza cut into 10 equal slices. You eat 3 slices.

Fraction
3/10

3 parts out of 10

Decimal
0.3

3 tenths

Percentage
30%

30 parts out of 100

Why do we need all three?

  • Fractions are exact — good for exact proportions (½ of a recipe)
  • Decimals work with calculators and place value
  • Percentages are easy to compare ("30% off" is simpler than "3/10 off")

Key equivalences to memorise

FractionDecimalPercentage
1/20.550%
1/40.2525%
3/40.7575%
1/100.110%
1/50.220%
1/30.333...33.3...%
2/30.666...66.6...%
1/80.12512.5%

Converting Between F, D and P

Three conversion routes — each is a simple calculation.

Fraction → Decimal → Percentage

F

Fraction to Decimal

Divide the numerator by the denominator.   3/4 → 3 ÷ 4 = 0.75

D

Decimal to Percentage

Multiply by 100.   0.75 × 100 = 75%

P

Percentage to Decimal

Divide by 100.   75% ÷ 100 = 0.75

Going back to a fraction

Decimal → FractionWrite as a fraction over a power of 10, then simplify.   0.6 = 6/10 = 3/5
Percentage → FractionWrite over 100, then simplify.   35% = 35/100 = 7/20

Fraction with any denominator → Percentage

MethodConvert denominator to 100 (multiply top and bottom), or: divide top by bottom × 100

Example: 7/20 → 7÷20 = 0.35 → 0.35×100 = 35%

Example: 3/5 → multiply by 20/20 → 60/100 = 60%

Interactive FDP Converter

Enter any fraction, decimal or percentage — the other two are calculated automatically with full working shown.

½ FDP Converter

Enter any one value to see all three forms

Fraction

Decimal

Percentage

Enter a value above to see the conversion steps.
Try these: Enter 3 and 8 as fraction → see 0.375 and 37.5%. Or enter 66.7 as percentage → see the decimal and fraction form.

Bar Model

A bar model shows the whole split into parts — a visual way to see F, D and P simultaneously.

Bar Model Visualiser

Add values that sum to 1 (100%) to build the model

Total
Enter values above to build the bar model.

Using bar models to compare

Bar models make it easy to see which fraction, decimal or percentage is larger without converting. The wider segment is the larger value.

  • Try: 0.5, 25%, 1/4 — do they sum to 1?
  • Try: 40%, 0.3, 3/10 — what do you notice?
  • Try: 1/3, 1/3, 1/3 — equal thirds

Practice

Select the correct answer.

Q1 — Fraction to percentage

What is 3/5 as a percentage?

Q2 — Decimal to fraction

What is 0.35 as a fraction in its simplest form?

Q3 — Ordering

Put these in order, smallest first: 0.6, 58%, 3/5

Q4 — Equivalence

Which of these is NOT equivalent to 1/4?

Exam Tips

Non-calculator — these methods must be fluent.

01

Memorise the common equivalences

½, ¼, ¾, 1/5, 1/10, 1/8 — know all three forms for each without calculating.

02

Convert to decimals to compare

When ordering a mix of F, D and P, convert everything to decimals first.

03

Always simplify fractions

35/100 is not fully simplified. Divide by the HCF. Mark schemes often require simplest form.

04

% to decimal: ÷ 100

Move the decimal point two places left. 75% → 0.75. Never divide by 10.

05

Recurring decimals from thirds

1/3 = 0.333... and 2/3 = 0.666... Use dots or write 0.3̄ to show recurrence.

06

Show conversion steps

In a multi-mark question, write the intermediate decimal. Missing this step loses method marks.

Calculations with Fractions

Adding, subtracting, multiplying and dividing fractions — all without a calculator.

Adding and subtracting fractions

Rule — must have a common denominatorFind the LCM of the denominators, convert, then add/subtract numerators.

Example: 3/4 + 2/5. LCM of 4 and 5 = 20. → 15/20 + 8/20 = 23/20 = 1 3/20

Example: 5/6 − 1/4. LCM = 12. → 10/12 − 3/12 = 7/12

Multiplying fractions

Multiply numerators, multiply denominators — then simplify3/4 × 2/5 = (3×2)/(4×5) = 6/20 = 3/10

Cancel common factors before multiplying to keep numbers small:

3/8 × 4/9 → cancel 3 and 9 (÷3), cancel 4 and 8 (÷4) → 1/2 × 1/3 = 1/6

Dividing fractions

Keep, Change, Flip — then multiplya/b ÷ c/d = a/b × d/c

Example: 3/4 ÷ 2/5 → 3/4 × 5/2 = 15/8 = 1 7/8

Example: 5/6 ÷ 5 = 5/6 ÷ 5/1 → 5/6 × 1/5 = 5/30 = 1/6

Mixed numbers

Convert mixed numbers to improper fractions before calculating.

Mixed → improper2 3/4 = (2×4+3)/4 = 11/4
Example: 1 1/2 × 2 2/3= 3/2 × 8/3 = 24/6 = 4

Fractions of amounts

Find 3/7 of £420£420 ÷ 7 × 3 = £60 × 3 = £180

Always divide by the denominator first to find one part, then multiply by the numerator.

Adding fractions — never add the denominators. 1/3 + 1/4 ≠ 2/7. Find a common denominator first: 4/12 + 3/12 = 7/12.

Learning Objectives

Tick each off as you go.

Where this fits

Number strand — calculator paper. Multipliers and reverse percentages appear in almost every GCSE paper. The double number line is the key structural tool for every type of percentage question.

Multipliers

A multiplier converts a percentage change into a single multiplication. This is the most efficient method on a calculator.

Finding the multiplier

SituationPercentageMultiplier
No change100%× 1.00
Increase by 15%115%× 1.15
Increase by 34%134%× 1.34
Decrease by 20%80%× 0.80
Decrease by 12%88%× 0.88
Decrease by 15%85%× 0.85
RuleIncrease: multiplier = (100 + %) ÷ 100   Decrease: multiplier = (100 − %) ÷ 100

Jamie's hotel rooms (from lesson)

Standard room: £422 per week

Room typePercentageMultiplierCost
Economy (20% off)80%× 0.80£337.60
Standard100%× 1.00£422.00
Deluxe (+15%)115%× 1.15£485.30
Super Deluxe (+34%)134%× 1.34£565.48
One calculation, one button press. Using a multiplier is faster and less prone to error than finding 10%, then 5%, then adding.

Percentage Calculator

Select the type of question, enter your values, and see the multiplier method with full working and a number line.

% Percentage Calculator

Multiplier method with double number line

Result
Select a question type and enter values.

Types of Percentage Question

There are five types. The multiplier method handles all of them.

Type 1 — Find a percentage of an amount

What is 30% of £360?

Multiplier = 30 ÷ 100 = 0.30Answer = 0.30 × 360 = £108

Type 2 — Percentage increase

Increase £422 by 15%.

100% + 15% = 115% → multiplier = 1.15Answer = 1.15 × 422 = £485.30

Type 3 — Percentage decrease

Decrease £422 by 20%.

100% − 20% = 80% → multiplier = 0.80Answer = 0.80 × 422 = £337.60

Type 4 — Amount as a percentage of another

£12 as a percentage of £60?

(part ÷ whole) × 100Answer = (12 ÷ 60) × 100 = 20%

Type 5 — Reverse percentage

After a 20% reduction, a price is £336. What was the original?

80% = £336 → multiplier = 0.80 → divide to reverseOriginal = 336 ÷ 0.80 = £420

Reverse Percentages

You are given the amount after the percentage change. You need to find the original (100%).

The key idea

The amount you are given is NOT 100%. It is the result after the change. Identify what percentage it represents, then divide.

MethodOriginal = given amount ÷ multiplier

If a price increased by 30% and is now £360: multiplier = 1.30. Original = 360 ÷ 1.30 = £276.92

If a price decreased by 15% and is now £13,600: multiplier = 0.85. Original = 13600 ÷ 0.85 = £16,000

Common error: Adding or subtracting the percentage from the given amount. You cannot do 13600 + 15% to find the original — this gives the wrong answer because 15% of 13600 is not the same as 15% of the original.

Exam question (Edexcel 2022)

The value of Michelle's car has decreased by 15%. It is now worth £13,600. Find the original value.

Decreased by 15% → now at 85% → multiplier = 0.85Original = 13,600 ÷ 0.85 = £16,000
£16,000. Check: 16000 × 0.85 = 13,600. ✓

Worked Examples

Holiday shopping context — try each calculation before reading the answer.

Example 1 — Percentage decrease

Sunglasses cost £32. Jamie has a 14% discount voucher. How much does he pay?

100% − 14% = 86% → multiplier = 0.86Cost = 0.86 × 32 = £27.52

Example 2 — Reverse percentage

Jamie bought shorts in a 14% off sale. He paid £32. What was the original price?

Sale price = 86% of original → multiplier = 0.86Original = 32 ÷ 0.86 = £37.21

Example 3 — Amount as a percentage

Laptop weighs 3.2kg. Baggage allowance is 14kg. What percentage does the laptop take?

(part ÷ whole) × 100Percentage = (3.2 ÷ 14) × 100 = 22.9%

Example 4 — Percentage increase

Suntan cream normally weighs 320g. Special offer has 14% extra. New weight?

100% + 14% = 114% → multiplier = 1.14Weight = 1.14 × 320 = 364.8g

Example 5 — Flight discount

July flight = £360. Book 4 months early for 30% off. Early booking cost?

100% − 30% = 70% → multiplier = 0.70Cost = 0.70 × 360 = £252

Practice

Select the correct answer.

Q1 — Multiplier

What is the multiplier for a 23% increase?

Q2 — Percentage decrease

A coat costs £85. It is reduced by 30% in a sale. What is the sale price?

Q3 — Amount as a percentage

A bag weighs 4.5kg. The baggage limit is 20kg. What percentage of the limit is the bag?

Q4 — Reverse percentage

After a 25% increase, a price is £250. What was the original price?

Q5 — Reverse percentage (exam style)

Michelle's car decreased by 15% in value. It is now worth £13,600. What was the original value?

Exam Tips

The most common mistakes in this topic.

01

Always use a multiplier

Finding 10% then 5% then adding is slower and more prone to error. Write the multiplier first.

02

Increase: add to 1. Decrease: subtract from 1.

+23% → 1.23. −23% → 0.77. Check: multiplier for decrease is always less than 1.

03

Reverse: divide, don't subtract

Do not take the percentage off the given amount. Divide by the multiplier. 336 ÷ 0.80, not 336 − 67.2.

04

Identify what 100% is

In reverse questions, the amount given is NOT 100%. State explicitly what percentage it represents before calculating.

05

Check by working forwards

Once you find the original, apply the multiplier and check you get back to the given amount.

06

Amount as % of another: (part ÷ whole) × 100

Make sure you divide the part by the whole (not the other way round).

Learning Objectives

Tick each off as you go.

Where this fits

Ratio, Proportion and Rates of Change — Foundation and Higher. Best buy questions appear in both calculator and non-calculator papers. They are straightforward but require a clear, structured method to avoid errors.

What are Best Buys?

A best buy question asks: which product gives you the most for your money?

The idea

Two products cost different amounts and contain different quantities. To compare them fairly, you need to find the cost per unit (per gram, per ml, per item).

Lower cost per unit = better value. The product with the smallest price per gram (or per ml, per item, etc.) is the best buy.

Two methods — both give the same answer

  • Method 1 — Price per unit: divide the price by the quantity. Smallest result = best buy.
  • Method 2 — Quantity per £1: divide the quantity by the price. Largest result = best buy.

Both methods work. Method 1 is slightly more intuitive. Always show which method you are using.

Real examples

  • Shampoo: 250ml for £2.50 vs 400ml for £3.60 — which is cheaper per ml?
  • Yoghurt: 6 pots for £2.70 vs 4 pots for £1.60 — which is cheaper per pot?
  • Washing powder: 1.5kg for £4.50 vs 2.5kg for £7.00 — which is cheaper per kg?

The Methods

Method 1 finds the price per unit. Method 2 finds how much you get per £1. Use either — they always agree.

Method 1 — Price per unit

FormulaPrice per unit = total price ÷ quantity

Compare the results: the smallest price per unit is the best value.

Example — Juice500ml for £1.20 → £1.20 ÷ 500 = £0.0024 per ml
750ml for £1.65 → £1.65 ÷ 750 = £0.0022 per ml ← Best buy

Method 2 — Quantity per £1

FormulaQuantity per £1 = quantity ÷ total price

Compare the results: the largest quantity per £1 is the best value.

Same example — Juice500ml for £1.20 → 500 ÷ 1.20 = 416.7 ml per £1
750ml for £1.65 → 750 ÷ 1.65 = 454.5 ml per £1 ← Best buy (more per £1)
Watch out: always use the same units when comparing. Convert grams to grams, ml to ml. Do not compare price per gram to price per kg without converting.

Steps to follow every time

1

Identify the two products

Note the price and quantity for each. Check units are the same.

2

Choose a method and apply it to both

Price per unit (÷ quantity) or quantity per £1 (÷ price). Must use same method for both.

3

Compare and state your conclusion

Write a clear conclusion naming the best buy. Just giving a number without a conclusion loses the mark.

Best Buy Calculator

Enter the price and quantity for up to three products. The calculator finds the unit rate for each and identifies the best buy.

🌆 Best Buy Comparison

Enter price and quantity for each product

PRODUCT A

Unit rate

PRODUCT B

Unit rate

PRODUCT C (optional)

Unit rate
Verdict
Enter values above
The calculator will compare unit rates and identify the best buy.
Try it: Product A: £2.50 for 250ml. Product B: £3.60 for 400ml. Product C: £4.80 for 600ml. Which is the best buy?

Worked Examples

Two methods shown side by side. You only need one in an exam.

Example 1 — Yoghurt

Pack A: 6 pots for £2.70. Pack B: 4 pots for £1.60. Which is better value?

ProductPriceQtyMethod 1 (p per pot)Method 2 (pots per £1)
Pack A£2.706 pots270 ÷ 6 = 45p each6 ÷ 2.70 = 2.22 per £1
Pack B£1.604 pots160 ÷ 4 = 40p each4 ÷ 1.60 = 2.50 per £1
Pack B is better value. 40p per pot < 45p per pot. (Or: 2.50 pots per £1 > 2.22 pots per £1.)

Example 2 — Washing powder

Small: 1.5 kg for £4.50. Large: 2.5 kg for £7.00. Which is better value?

ProductPriceQtyPrice per kg
Small£4.501.5 kg£4.50 ÷ 1.5 = £3.00 per kg
Large£7.002.5 kg£7.00 ÷ 2.5 = £2.80 per kg
Large is better value. £2.80 per kg < £3.00 per kg.

Example 3 — Three options

Shampoo: 200ml for £1.80, 350ml for £2.94, 500ml for £4.25. Best buy?

ProductPriceQuantityPence per ml
200ml£1.80200ml180 ÷ 200 = 0.90p per ml
350ml£2.94350ml294 ÷ 350 = 0.84p per ml
500ml£4.25500ml425 ÷ 500 = 0.85p per ml
350ml is the best buy at 0.84p per ml — cheaper than both alternatives, even though it is not the largest size.

Practice

Select the correct answer.

Q1 — Unit rate

Cereal A: 750g for £2.10. Cereal B: 1000g for £2.60. Which is better value?

Q2 — Method choice

Which calculation correctly finds the price per gram for a 400g pack costing £2.80?

Q3 — Three products

Orange juice: Small 330ml for 99p. Medium 500ml for £1.45. Large 750ml for £2.10. Which is the best buy?

Q4 — Converting units

Pasta: 500g for £0.85 vs 1.2kg for £1.90. Which is better value?

Exam Tips

Best buy questions are reliable marks — do not give them away.

01

Always show the unit rate for both products

Even if the answer seems obvious, you need both unit rates written down. Both carry marks.

02

Write a clear conclusion

Name the product. "Product B is better value because it has a lower price per gram." One word answers lose the final mark.

03

Convert units before comparing

If one product is in grams and another in kg, convert to the same unit first.

04

Work in pence, not pounds

Multiplying by 100 first (£ to p) avoids small decimals and reduces rounding errors.

05

Bigger is not always better value

Do not assume the larger pack is always cheaper per unit. Always calculate — Example 3 shows this.

06

Use the same method for all products

Use Method 1 for all, or Method 2 for all. Mixing methods within a question risks comparison errors.

Learning Objectives

Tick each off as you go.

Where this fits

Algebra strand — Foundation and Higher. Linear (arithmetic) nth term is Foundation. Quadratic nth term is Higher only. Sequences questions appear on both calculator and non-calculator papers.

Sequences

A sequence is a list of numbers that follow a pattern. Each number in the sequence is called a term.

Types of sequence

TypePatternExampleNth term
Arithmetic (linear)Add or subtract same amount each time3, 7, 11, 15, 19...4n − 1
GeometricMultiply by same ratio each time2, 6, 18, 54...2 × 3ⁿ⁻¹
QuadraticSecond difference is constant1, 4, 9, 16, 25...
Fibonacci-styleEach term = sum of two previous terms1, 1, 2, 3, 5, 8...No simple formula

Key vocabulary

  • Term — a number in the sequence. The 1st term, 2nd term, etc.
  • Common difference (d) — the amount added each time in an arithmetic sequence
  • First term (a) — the value when n = 1
  • Nth term — a formula that gives the value of any term. Substitute n = 1, 2, 3... to get the sequence back.

First difference check

Write the sequence, then write the differences between consecutive terms below them.

Example: 5, 9, 13, 17, 21...Differences: +4, +4, +4, +4 — constant = arithmetic sequence
Example: 1, 4, 9, 16, 25...1st differences: 3, 5, 7, 9 — not constant
2nd differences: +2, +2, +2 — constant = quadratic sequence

Arithmetic (Linear) Sequences

The most common type at GCSE. The nth term formula is always of the form dn + c.

The formula

Nth term of an arithmetic sequencenth term = dn + c

Where d is the common difference and c is found by substituting n = 1 and solving.

Four-step method

1

Find the common difference d

Subtract any term from the next: T₂ − T₁ = d. Check it is the same throughout.

2

Write dn + c

Write the coefficient of n. For example, if d = 4, write 4n + c.

3

Find c

Substitute n = 1 and T₁ (the first term). Solve for c. Example: 4(1) + c = 5 → c = 1.

4

Write and check the formula

Write the complete formula, then substitute n = 1, 2, 3 to verify it gives back the original sequence.

Is a number in the sequence?

MethodSet nth term = the number. Solve for n. If n is a positive whole number, the number is in the sequence.

Example: is 85 in the sequence 4n + 1? → 4n + 1 = 85 → 4n = 84 → n = 21. Yes — it is the 21st term.

Example: is 50 in the sequence 4n + 1? → 4n + 1 = 50 → 4n = 49 → n = 12.25. No — not a whole number.

Nth Term Calculator

Enter the first few terms of your sequence. The calculator finds the common difference, works out the nth term formula, and lists any term you choose.

Nth Term Calculator

Enter the first 4 terms of your arithmetic sequence

Nth term formula
Enter the first four terms above.
Value of that term

First 10 terms of your sequence

Try: Enter 3, 7, 11, 15. The formula should be 4n − 1. Check: is 99 in the sequence? → 4n − 1 = 99 → n = 25. Yes!

Quadratic Sequences (Higher)

The second difference is constant. The nth term contains an n² term.

Identifying a quadratic sequence

Write the first differences (T₂−T₁, T₃−T₂, etc.), then the second differences. If the second differences are constant and non-zero, the sequence is quadratic.

Example: 2, 5, 10, 17, 26...1st differences: 3, 5, 7, 9
2nd differences: 2, 2, 2 — constant → quadratic

Method for quadratic nth term

1

Find a — the coefficient of n²

a = second difference ÷ 2. For second difference = 2: a = 1. The nth term starts with n².

2

Subtract an² from each term

This gives a new sequence (the remainder). Find the nth term of that remainder sequence — it will be linear (dn + c).

3

Combine: nth term = an² + dn + c

Write the full quadratic formula and verify against the original sequence.

Worked example: 2, 5, 10, 17, 26...

Second difference = 2 → a = 1 → start with n²

nTermTerm − n²
1211
2541
31091
417161

Remainder = 1, 1, 1, 1 → constant → the linear part is just +1.

Nth term = n² + 1. Check: n=3 → 9+1=10 ✓
Higher only: Quadratic nth term is not required at Foundation level. If the second difference is not constant, the sequence is neither linear nor quadratic.

Worked Examples

Try each before reading the answer.

Example 1 — Find the nth term

Sequence: 7, 11, 15, 19, 23...

Step 1 — common differenced = 11 − 7 = 4
Step 2 — write 4n + cSubstitute n=1, T₁=7: 4(1) + c = 7 → c = 3
Step 3 — formula and checknth term = 4n + 3   Check: n=2 → 11 ✓, n=3 → 15 ✓

Example 2 — Negative common difference

Sequence: 20, 17, 14, 11, 8...

d = 17 − 20 = −3. Write −3n + c.n=1, T₁=20: −3(1) + c = 20 → c = 23
Formulanth term = −3n + 23   Check: n=3 → −9+23=14 ✓

Example 3 — Is 100 in the sequence 7n − 2?

Set nth term = 1007n − 2 = 100 → 7n = 102 → n = 14.57...
Not a whole number, so 100 is not in the sequence.

Example 4 — Find a specific term

The nth term is 5n − 3. Find the 12th term.

Substitute n = 125(12) − 3 = 60 − 3 = 57

Practice

Select the correct answer.

Q1 — Common difference

What is the common difference of the sequence: 6, 10, 14, 18, 22...?

Q2 — Find nth term

What is the nth term of the sequence: 3, 8, 13, 18, 23...?

Q3 — Use the formula

The nth term is 6n − 1. What is the 15th term?

Q4 — Is it in the sequence?

nth term = 4n + 3. Is 47 in this sequence?

Exam Tips

The most common errors in this topic.

01

Always verify your formula

Substitute n = 1, 2, 3 back in. If you do not get the original sequence, recheck c.

02

d can be negative

A decreasing sequence has a negative common difference. Write −dn + c — keep the sign throughout.

03

For "is X in the sequence?" always solve for n

Set nth term = X, solve, check n is a positive integer. Do not just list terms — you may stop too early.

04

Do not confuse nth term with the next term

The nth term is a formula, not the next number in the list. Substituting n = 5 gives the 5th term, not the term after the 4th.

05

Quadratic: second difference ÷ 2 gives the n² coefficient

Always find the second differences first. If first differences are not constant, move on to second differences.

06

Show your difference working

Write the sequence, then write the differences beneath it. Showing this earns method marks even if the formula is wrong.

Learning Objectives

Tick each off as you go.

Where this fits

Ratio, Proportion and Rates of Change — Foundation and Higher. Unit conversions are non-calculator friendly. Map scale questions appear regularly and combine measurement with ratio.

Metric Units

The metric system uses powers of 10. Every conversion is a multiplication or division by 10, 100 or 1000.

Length

Conversions10 mm = 1 cm  ·  100 cm = 1 m  ·  1000 m = 1 km

To convert to a smaller unit: multiply. To convert to a larger unit: divide.

Example: 3.4 km = 3.4 × 1000 = 3400 m    Example: 750 cm = 750 ÷ 100 = 7.5 m

Mass

Conversions1000 mg = 1 g  ·  1000 g = 1 kg  ·  1000 kg = 1 tonne

Capacity (Volume of liquids)

Conversions1000 ml = 1 litre  ·  100 cl = 1 litre  ·  1 ml = 1 cm³
Memory trick — "King Henry Died By Drinking Cold Milk" (kilo, hecto, deca, base, deci, centi, milli). Each step is × or ÷ 10.

Imperial & Conversions

Imperial units are not based on powers of 10. Conversion factors are always given in the exam — you just need to know how to use them.

Key approximations you must know

ImperialMetric (approx)Use
1 inch2.54 cmlength
1 foot30 cmlength
1 mile1.6 kmdistance
1 kg2.2 poundsmass
1 gallon4.5 litrescapacity
1 pint568 mlcapacity

Using conversion factors

MethodIdentify the conversion factor. Multiply or divide depending on direction.

Example: Convert 8 miles to km.   1 mile = 1.6 km → 8 × 1.6 = 12.8 km

Example: Convert 5 kg to pounds.   1 kg = 2.2 lb → 5 × 2.2 = 11 pounds

Example: Convert 9 gallons to litres.   1 gallon = 4.5 l → 9 × 4.5 = 40.5 litres

Direction matters: when converting from a larger unit to a smaller one, multiply. When converting from smaller to larger, divide. A quick sanity check — 5 miles should be more km than miles, so multiply.

Unit Converter

Select a conversion type, enter a value, and see the result with full working shown.

🗺 Unit Converter

Metric and imperial conversions with working shown

Result
Select a conversion type and enter a value.

Map Scales

A map scale tells you how many units in real life are represented by one unit on the map. Written as a ratio 1 : n.

Reading a scale

1 : 25 000 means1 cm on the map = 25 000 cm in real life = 250 m = 0.25 km

The second number in the ratio tells you how many times bigger reality is than the map.

Map → Real life

FormulaReal distance = map distance × scale factor

Example: Scale 1 : 50 000. Map distance = 4 cm. Real = 4 × 50 000 = 200 000 cm = 2000 m = 2 km

Real life → Map

FormulaMap distance = real distance ÷ scale factor

Example: Scale 1 : 25 000. Real distance = 3.5 km = 350 000 cm. Map = 350 000 ÷ 25 000 = 14 cm

Map Scale Calculator

Convert between map and real distances

Results
Enter a scale factor and one distance to calculate the other.
Always convert to the same unit before calculating. Work in centimetres throughout — convert km to cm (× 100 000) or m to cm (× 100) first, then divide by the scale factor.

Practice

Select the correct answer.

Q1 — Metric conversion

How many metres are in 3.7 km?

Q2 — Imperial conversion

A car journey is 45 miles. Using 1 mile ≈ 1.6 km, how far is this in km?

Q3 — Map scale

A map has scale 1 : 50 000. A road measures 6 cm on the map. What is the real length in km?

Q4 — Real to map

Scale 1 : 25 000. A field is 1.5 km long. How long is it on the map in cm?

Exam Tips

The most common errors in this topic.

01

Convert to the same unit before comparing

Never compare cm with m or km with m directly. Convert first — this is the most common error.

02

Smaller unit = multiply

Going from km to m (smaller): multiply by 1000. Going from m to km (larger): divide by 1000.

03

Map: multiply to get real, divide to get map

Map → Real: × scale. Real → Map: ÷ scale. Always work in cm.

04

Convert km to cm for map questions

km × 100 000 = cm. Do this conversion before dividing by the scale factor.

05

Imperial conversions are always given

You do not need to memorise exact imperial conversions — but you must know roughly which way to convert (multiply or divide).

06

Sense-check your answer

5 miles should be about 8 km (not 3 km, not 80 km). Always check your answer is in the right ballpark.

Learning Objectives

Tick each off as you go.

The SDT Triangle

Cover the quantity you want to find — the triangle shows the formula.

D S T ×

Cover D → Distance = S × T    Cover S → Speed = D ÷ T    Cover T → Time = D ÷ S

The three formulas

SpeedS = D ÷ T
DistanceD = S × T
TimeT = D ÷ S

Units must match

  • If speed is in km/h and time is in hours → distance is in km
  • If speed is in m/s and time is in seconds → distance is in metres
  • If time is given in minutes, convert to hours first: divide by 60
  • If time is given in seconds, convert to hours: divide by 3600
Average speed = total distance ÷ total time. Not the average of the two speeds. You must add both distances and both times separately first.

SDT Calculator

Select your units, enter two values — the calculator finds the third with full working shown.

Speed, Distance & Time Calculator

Leave one field blank — that is the value that will be calculated

Result
Select units, enter any two values and leave the unknown blank.
Unit tip: If speed is km/h, time must be in hours.
If speed is m/s, time must be in seconds.
The calculator keeps your chosen units — just make sure they match.
90 minutes = 1.5 hours. Always convert minutes to hours (÷ 60) before using km/h.

Time Conversions

The trickiest part of SDT problems. Always convert time to a decimal before using formulas.

Converting time to decimals

TimeIn hours (decimal)Calculation
30 minutes0.5 hours30 ÷ 60
45 minutes0.75 hours45 ÷ 60
1 hour 30 min1.5 hours1 + 30/60
2 hours 20 min2.333... hours2 + 20/60
1 hour 15 min1.25 hours1 + 15/60

Converting decimal hours back to minutes

MethodMultiply the decimal part by 60 to get minutes

Example: 2.75 hours = 2 hours and 0.75 × 60 = 45 minutes = 2 hours 45 minutes

Example: 1.4 hours = 1 hour and 0.4 × 60 = 24 minutes = 1 hour 24 minutes

Do not treat hours and minutes like decimals. 1 hour 30 minutes ≠ 1.30 hours. It is 1.5 hours. Always convert: minutes ÷ 60.

Worked Examples

Try each before reading the answer.

Example 1 — Finding speed

A car travels 240 km in 3 hours. Find the average speed.

S = D ÷ TSpeed = 240 ÷ 3 = 80 km/h

Example 2 — Time in minutes

A train travels at 120 km/h. How far does it travel in 45 minutes?

Convert: 45 min = 45 ÷ 60 = 0.75 hoursD = S × T = 120 × 0.75 = 90 km

Example 3 — Finding time

A cyclist travels 36 km at 12 km/h. How long does the journey take?

T = D ÷ STime = 36 ÷ 12 = 3 hours

Example 4 — Average speed (two stages)

Stage 1: 60 km at 30 km/h. Stage 2: 90 km at 60 km/h. Find average speed for whole journey.

Time stage 1: 60÷30 = 2 h. Time stage 2: 90÷60 = 1.5 hAverage speed = (60+90) ÷ (2+1.5) = 150 ÷ 3.5 = 42.9 km/h
Do NOT average the two speeds: (30+60)÷2 = 45. Wrong. Always use total distance ÷ total time.

Practice

Select the correct answer.

Q1 — Speed

A bus travels 180 km in 2.5 hours. What is its average speed?

Q2 — Time conversion

A car travels at 60 km/h for 1 hour 20 minutes. How far does it travel?

Q3 — Average speed

A cyclist rides 20 km at 10 km/h, then 30 km at 15 km/h. What is the average speed?

Exam Tips

Speed, distance and time questions are reliable marks.

01

Convert minutes to hours first

Divide minutes by 60 before substituting. 1 hr 30 min = 1.5 h, not 1.3 h.

02

Average speed ≠ average of speeds

Always use total distance ÷ total time. Averaging the speeds gives the wrong answer.

03

Check units match throughout

Speed in km/h needs distance in km and time in hours. Mixing units is the most common error.

04

State the formula first

Write S = D ÷ T (or whichever applies) before substituting. Earns a method mark.

05

Convert answer back to h:min if asked

If the question asks for time in hours and minutes, multiply the decimal part by 60.

06

Distance-time graph: gradient = speed

A steeper slope means higher speed. A horizontal line means stationary.

Learning Objectives

Tick each off as you go.

Ratio Basics

A ratio compares two or more quantities. It is written using a colon: 3 : 5 means 3 parts to 5 parts.

Writing and simplifying ratios

HCF — Highest Common Factor is the largest number that divides exactly into all parts of the ratio. For example, the HCF of 12 and 8 is 4, because 4 is the biggest number that goes into both 12 and 8 without a remainder. To find it, list the factors of each number and pick the biggest one they share.
To simplify: divide all parts by the HCF12 : 8 → HCF of 12 and 8 is 4 → 12÷4 : 8÷4 = 3 : 2

Example: Simplify 15 : 25. Factors of 15: 1,3,5,15. Factors of 25: 1,5,25. HCF = 5. → 15÷5 : 25÷5 = 3 : 5

Example: Simplify 24 : 16 : 8. HCF of all three = 8. → 24÷8 : 16÷8 : 8÷8 = 3 : 2 : 1

Equivalent ratios

Like equivalent fractions — multiply or divide all parts by the same number.

Example: 2 : 3× 2 → 4 : 6    × 5 → 10 : 15    all equivalent to 2 : 3

Unitary form (1 : n)

Divide both sides by the first number to get a ratio in the form 1 : n. Useful for comparing ratios.

Example: 3 : 7 → divide both by 3 → 1 : 2.33...

Example: 4 : 5 → divide both by 4 → 1 : 1.25

Sharing in a Ratio

The most common ratio question type. Three clear steps every time.

Three-step method

1

Find the total number of parts

Add all the numbers in the ratio. e.g. 3 : 2 → total parts = 5.

2

Find the value of one part

Divide the total amount by the total number of parts.

3

Multiply to find each share

Multiply the value of one part by each number in the ratio.

Example — sharing £60 in ratio 3 : 2

Step 1: total parts3 + 2 = 5 parts
Step 2: value of 1 part£60 ÷ 5 = £12 per part
Step 3: each shareFirst share: 3 × £12 = £36    Second share: 2 × £12 = £24
Check: £36 + £24 = £60. ✓

When one part is given

Sometimes the question gives you one share and asks you to find the total or another share.

MethodFind the value of 1 part from the given share, then scale up

Example: A and B share money in ratio 3 : 5. A gets £36. Find B's share and the total.

A's share = 3 parts = £36 → 1 part = £36 ÷ 3 = £12

B's share = 5 × £12 = £60. Total = 8 × £12 = £96

Ratio and Fractions

Every ratio can be written as fractions. This connection is very commonly tested.

Converting ratio to fractions

RuleEach part of the ratio ÷ total parts = that share as a fraction of the whole

Example: Ratio 3 : 5. Total parts = 8.

First share = 3/8 of the whole. Second share = 5/8 of the whole.

Converting fractions to ratio

Write both fractions over the same denominator, then the numerators form the ratio.

Example: ⅜ and ⅝ → ratio = 3 : 5

Example: ¼ and ¾ → ratio = 1 : 3

Example: ⅓ and ½ → common denominator 6 → 2/6 and 3/6 → ratio = 2 : 3

Combined ratio and fraction problems

Example: ⅖ of a bag of sweets are red. The rest are blue and green in ratio 2 : 3. What fraction are green?

Red = 2/5. Remaining = 3/5. Blue : Green = 2 : 3 → green = 3/5 of remaining = 3/5 × 3/5 = 9/25

Interactive Ratio Splitter

Enter a total and a ratio — the splitter divides it and shows each share as a fraction and amount.

∶ Ratio Splitter

Enter a total and ratio parts (up to 4 parts)

Shares
Enter a total and ratio parts.

Practice

Select the correct answer.

Q1 — Simplify

Simplify the ratio 18 : 24.

Q2 — Sharing

Share £84 in ratio 3 : 4. How much does the larger share receive?

Q3 — Ratio to fraction

In a class, boys and girls are in ratio 2 : 3. What fraction of the class are girls?

Q4 — One part given

A and B share money in ratio 3 : 7. B receives £105. How much does A receive?

Exam Tips

Common ratio errors to avoid.

01

Always find the value of 1 part first

Divide total by total parts. Then scale up. Do not try to do it in one step.

02

Check by adding the shares

Shares must add back to the original total. If they do not, recheck your working.

03

Simplify ratios using HCF, not just any factor

Divide by the highest common factor to reach the simplest form in one step.

04

Ratio to fraction: use total parts as denominator

a : b → fractions are a/(a+b) and b/(a+b). Not a/b.

05

When one part is given, find 1 part first

Divide the given amount by its ratio number to get 1 part. Then multiply for all others.

06

Three-part ratios: total all three

a : b : c → total parts = a + b + c. Same method, just three shares instead of two.

Percentage Change

Percentage change measures how much a value has increased or decreased relative to the original.

Percentage change formula

Percentage change% change = (change ÷ original) × 100
Percentage increase% increase = (new − original) ÷ original × 100
Percentage decrease% decrease = (original − new) ÷ original × 100

Worked examples

A jumper costs £45 in January and £54 in February. Find the percentage increase.

% increase(54−45) ÷ 45 × 100 = 9 ÷ 45 × 100 = 20%

A car was bought for £12,000 and sold for £9,000. Find the percentage loss.

% decrease(12000−9000) ÷ 12000 × 100 = 3000 ÷ 12000 × 100 = 25%

Percentage change with multipliers

New value after % increaseNew = original × (1 + r/100)
New value after % decreaseNew = original × (1 − r/100)

Example: 15% increase on £240 → 240 × 1.15 = £276

Example: 8% decrease on £500 → 500 × 0.92 = £460

Repeated percentage change

After n applications of multiplier kFinal = original × kⁿ

Example: £1000 invested at 3% per year for 4 years.

Compound interest1000 × 1.03⁴ = 1000 × 1.1255 = £1125.51

Example: Car worth £20,000 depreciates 12% per year for 3 years.

Depreciation20000 × 0.88³ = 20000 × 0.6815 = £13,629
Always divide by the ORIGINAL value, not the new value. A common error is dividing by the new (larger or smaller) amount.

Proportion

Direct proportion — as one quantity increases, the other increases at the same rate. Inverse proportion — as one increases, the other decreases.

Direct proportion

y is directly proportional to xy ∝ x    y = kx
y is directly proportional to x²y = kx²
y is directly proportional to √xy = k√x

Example: y ∝ x. When x=4, y=12. Find k: k=12÷4=3. Equation: y=3x. Find y when x=7: y=3×7=21

Inverse proportion

y is inversely proportional to xy ∝ 1/x    y = k/x    so xy = k (constant)
y is inversely proportional to x²y = k/x²

Example: y ∝ 1/x. When x=3, y=8. Find k: k=3×8=24. Equation: y=24/x. Find y when x=6: y=24/6=4

Inverse proportion graph is a reciprocal curve — as x increases, y decreases but never reaches zero.

Recognising proportion type

If you double x and y...TypeEquation
...also doublesDirect (y ∝ x)y = kx
...quadruples (×4)Direct squared (y ∝ x²)y = kx²
...halves (÷2)Inverse (y ∝ 1/x)y = k/x
...quarters (÷4)Inverse squared (y ∝ 1/x²)y = k/x²

Learning Objectives

Tick each off as you go.

Long Multiplication

The grid method and column method both work — use whichever you find more reliable.

Grid method — 347 × 26

×300407
206000800140
6180024042
Sum all cells6000 + 800 + 140 + 1800 + 240 + 42 = 9022

Column method — 347 × 26

Step 1: 347 × 6 = 2082Step 2: 347 × 20 = 6940
Step 3: 2082 + 6940 = 9022

Multiply by each digit separately, then add the results.

Multiplying decimals

Ignore the decimal point, multiply as integers, then count total decimal places in the original numbers and insert the point in the answer.

Example: 3.4 × 1.2 → 34 × 12 = 408 → 2 decimal places total → 4.08

Long Division

Work through the dividend digit by digit, left to right.

Method — 952 ÷ 8

1

How many times does 8 go into 9?

Once (1 × 8 = 8). Write 1 above. Remainder: 9 − 8 = 1. Bring down the 5 → 15.

2

How many times does 8 go into 15?

Once (1 × 8 = 8). Write 1 above. Remainder: 15 − 8 = 7. Bring down 2 → 72.

3

How many times does 8 go into 72?

9 times (9 × 8 = 72). Write 9 above. Remainder: 0.

Answer: 952 ÷ 8 = 119. Check: 119 × 8 = 952. ✓

Dividing decimals

MethodMultiply both numbers by a power of 10 to make the divisor a whole number

Example: 4.5 ÷ 0.3 → multiply both by 10 → 45 ÷ 3 = 15

Example: 2.4 ÷ 0.08 → multiply both by 100 → 240 ÷ 8 = 30

Rounding & Significant Figures

Two different rounding systems — both essential for the non-calculator paper.

Decimal places (d.p.)

Count digits after the decimal point. Look at the next digit: if ≥ 5, round up; if < 5, leave unchanged.

3.7462 rounded to:1 d.p. → 3.7    2 d.p. → 3.75    3 d.p. → 3.746

Significant figures (s.f.)

Start counting from the first non-zero digit. Round using the same ≥5 rule.

3746.2 rounded to:1 s.f. → 4000    2 s.f. → 3700    3 s.f. → 3750
0.004628 rounded to:1 s.f. → 0.005    2 s.f. → 0.0046    3 s.f. → 0.00463
Leading zeros are not significant. In 0.00463, the first significant figure is 4, not 0. In 3700, if rounded to 2 s.f., the zeros are placeholders — they are not significant.

Estimating

Round every number to 1 significant figure, then calculate. This gives an approximate answer to check your working.

Method

1

Round each number to 1 significant figure

38.4 → 40, 6.7 → 7, 0.48 → 0.5, 312 → 300

2

Calculate using the rounded values

Use the simpler numbers to do a quick mental calculation.

3

Write the estimate and compare

Use ≈ (approximately equal to). If your calculator answer is very different, recheck.

Examples

Estimate: 38.4 × 6.7≈ 40 × 7 = 280    (exact: 257.28)
Estimate: 312 ÷ 4.8≈ 300 ÷ 5 = 60    (exact: 65)
Estimate: (48.3 × 19.7) ÷ 3.8≈ (50 × 20) ÷ 4 = 1000 ÷ 4 = 250    (exact: 250.5)
Estimation questions on the exam: show all rounded values explicitly. Write: "38.4 ≈ 40, 6.7 ≈ 7" before calculating. Missing this step loses marks.

Practice

Non-calculator — work these out by hand.

Q1 — Long multiplication

Calculate 36 × 24 without a calculator.

Q2 — Significant figures

Round 0.005847 to 2 significant figures.

Q3 — Estimation

Estimate the value of (48.7 × 3.2) ÷ 4.9

Exam Tips

Non-calculator technique matters.

01

Show all working for long multiplication

Split into partial products. Write each one separately. Easy to check and earns method marks.

02

Check multiplication with a reverse operation

If 347 × 26 = 9022, check by estimating: 350 × 25 = 8750 ≈ 9022. Reasonable.

03

Leading zeros are not significant

0.0047 has 2 significant figures: 4 and 7. The zeros are placeholders, not significant.

04

Show rounded values explicitly in estimation

Write each number rounded to 1 s.f. before calculating. Missing this step loses marks even if the estimate is correct.

05

Dividing by a decimal: scale both up

2.4 ÷ 0.08 → × 100 → 240 ÷ 8 = 30. Much easier than dividing by a decimal directly.

06

Estimate first on calculator papers too

Use an estimate to sense-check your calculator answer before writing it down.

Learning Objectives

Tick each off as you go.

Exchange Rates

An exchange rate tells you how many units of one currency equal one unit of another.

The key rule

£1 = 1.17 euros meansTo convert £ → euros: multiply by 1.17
To convert euros → £: divide by 1.17

Example: Convert £250 to euros at £1 = €1.17. → 250 × 1.17 = €292.50

Example: Convert €180 to pounds at £1 = €1.17. → 180 ÷ 1.17 = £153.85

Comparing prices in different currencies

Convert all prices to the same currency, then compare.

Example: A laptop costs £680 in the UK and $850 in the US. Rate: £1 = $1.28. Is the UK or US cheaper?

Convert $850 to pounds: 850 ÷ 1.28 = £664.06. The US is cheaper by £680 − £664.06 = £15.94.

Commission and charges

Some currency exchanges charge commission — a percentage deducted from the amount exchanged.

Amount after commissionAmount × (1 − commission%) → then × exchange rate

Example: Exchange £500 at €1.15 per £, 2% commission. Amount after commission = 500 × 0.98 = £490. Then 490 × 1.15 = €563.50.

Currency Calculator

Enter an amount and exchange rate — converts in both directions with working shown.

💲 Currency Converter

Enter a rate and amount to convert

Results
Enter an exchange rate and amount to convert.

Ratio and Percentages Combined

Multi-step problems linking ratio, fractions and percentages — very common at Higher tier.

Expressing a ratio share as a percentage

If profit is shared in ratio 3 : 7, the first person gets 3/(3+7) = 3/10 = 30%

RuleFraction of total = part ÷ total parts → convert to % by × 100

Percentage change applied to ratio share

Example: Two friends invest in ratio 2 : 3. The investment grows by 18%. How much does each receive if they started with £5000?

Find shares: total 5 parts. 1 part = £1000.A = 2 parts = £2000. B = 3 parts = £3000.
Apply 18% growth to each:A → 2000 × 1.18 = £2360    B → 3000 × 1.18 = £3540
Check: £2360 + £3540 = £5900 = £5000 × 1.18 ✓

Ratio as percentage — exam question type

Example: In a school, students study French, Spanish, German in ratio 5 : 3 : 2. What percentage study German?

Total parts = 10. German = 2 parts. Fraction = 2/10. Percentage = 20%

Worked Examples

Full multi-step solutions.

Example 1 — Holiday money

Sarah exchanges £350 to euros at £1 = €1.14. The bank charges 1.5% commission. How many euros does she receive?

Step 1: commission deducted£350 × (1 − 0.015) = 350 × 0.985 = £344.75
Step 2: convert to euros344.75 × 1.14 = €393.02

Example 2 — Best price comparison

A watch costs £145 in the UK and $180 in the US. Exchange rate: £1 = $1.27. Which is cheaper and by how much (in £)?

Convert US price to £180 ÷ 1.27 = £141.73
US price (£141.73) < UK price (£145). US is cheaper by £145 − £141.73 = £3.27

Example 3 — Ratio, percentage, combined

Three siblings share an inheritance of £24 000 in ratio 1 : 2 : 3. The youngest invests her share and earns 8% interest. How much does she have after interest?

Total 6 parts. 1 part = £4000. Youngest = 1 part = £4000£4000 × 1.08 = £4320

Practice

Select the correct answer.

Q1 — Currency conversion

£1 = $1.32. Convert £220 to dollars.

Q2 — Convert back

£1 = €1.15. A meal costs €46. What is this in pounds?

Q3 — Ratio to percentage

Profits are shared in ratio 2 : 3 : 5. What percentage does the largest share receive?

Q4 — Combined

£8000 is shared in ratio 3 : 5. The larger share is invested at 10% interest. What is the final value of that share?

Exam Tips

Exchange rate and combined questions — work methodically.

01

To convert to foreign currency: multiply

£ → euros: multiply by the rate. Euros → £: divide by the rate.

02

Commission is applied before conversion

Deduct commission from the original amount first, then apply the exchange rate.

03

Always convert to the same currency to compare

Never compare prices in different currencies directly. Convert both to £ or both to the foreign currency.

04

For ratio + %: find the ratio share first

Split the total into shares using ratio. Then apply the percentage to the relevant share.

05

Ratio to %: part ÷ total parts × 100

Show this step explicitly. The ratio numbers are not the percentages.

06

Check combined answers

After applying % to each ratio share, check that the total matches the expected result (e.g. whole × multiplier).

Learning Objectives

Tick each off as you go.

Where this fits

Algebra and Number — both papers. Non-calculator questions test knowledge of squares and cubes to 15². Calculator questions test index laws and fractional indices.

Powers & Roots

A power tells you how many times a number is multiplied by itself.

Index notation

aⁿ means a × a × ... (n times)2⁵ = 2×2×2×2×2 = 32   3⁴ = 81   10³ = 1000

The number being raised is the base. The power is the index or exponent.

Key squares and cubes to memorise

nn
111636216
248749343
3927864512
41664981729
525125101001000
1214415225

Roots

Square root√49 = 7 because 7² = 49   √144 = 12
Cube root∛27 = 3 because 3³ = 27   ∛125 = 5

Negative and fractional indices

Negative index — reciprocala⁻ⁿ = 1 ÷ aⁿ   2⁻³ = 1/8   5⁻² = 1/25
Fractional index — roota^(1/n) = nth root of a   8^(1/3) = 2   16^(1/2) = 4
Combined: a^(m/n)= (nth root of a)^m   8^(2/3) = (∛8)² = 4

Index Laws

Six rules for simplifying expressions with powers. Bases must match for laws 1–3.

The six laws

Law 1 — Multiply: add powersaᵐ × aⁿ = aᵐ⁺ⁿ   x³ × x⁵ = x⁸
Law 2 — Divide: subtract powersaᵐ ÷ aⁿ = aᵐ⁻ⁿ   y⁷ ÷ y² = y⁵
Law 3 — Power of a power: multiply(aᵐ)ⁿ = aᵐⁿ   (x²)⁴ = x⁸
Law 4 — Zero power = 1a⁰ = 1   7⁰ = 1   x⁰ = 1
Law 5 — Negative power: reciprocala⁻ⁿ = 1/aⁿ   3⁻² = 1/9
Law 6 — Fractional power: roota^(1/n) = ⁿ√a   27^(1/3) = 3
Laws only apply when the base is the same. x³ × y² cannot be simplified — x and y are different bases.

Powers Calculator

Enter a base and power, or find a square/cube root.

Powers & Roots Calculator

Result
Enter a base and power.

Practice

Q1 — Index law

Simplify x⁴ × x⁶

Q2 — Negative index

What is 4⁻²?

Q3 — Fractional index

What is 27^(2/3)?

Exam Tips

01

Same base to apply laws

x³ × y² cannot be simplified — the bases differ.

02

a⁰ = 1 always

Any base raised to the power zero equals 1.

03

Negative index = flip

a⁻ⁿ = 1/aⁿ. If a is a fraction, it flips.

04

Fractional: denominator = root type

a^(1/3) = cube root. The denominator tells you which root.

05

Root first, then power

For a^(m/n): find the root first — keeps numbers smaller.

06

Memorise squares to 15 and cubes to 10

These appear on almost every non-calculator paper.

Factors & Multiples

Factors divide exactly into a number. Multiples are in a number's times table.

Definitions

HCF — Highest Common Factor

HCF of two numbersThe largest number that divides exactly into both

Find HCF(24, 36): Factors of 24: 1,2,3,4,6,8,12,24. Factors of 36: 1,2,3,4,6,9,12,18,36. Common: 1,2,3,4,6,12. HCF = 12

Use HCF to simplify fractions: 24/36 → ÷12 → 2/3

LCM — Lowest Common Multiple

LCM of two numbersThe smallest number that is a multiple of both

Find LCM(8, 12): Multiples of 8: 8,16,24,32… Multiples of 12: 12,24,36… LCM = 24

Use LCM to add fractions with different denominators: 1/8 + 1/12 → denominator = 24 → 3/24 + 2/24 = 5/24

HCF × LCM = product of the two numbers. HCF(8,12) × LCM(8,12) = 4 × 24 = 96 = 8 × 12. Use this as a check.

Prime Factor Decomposition

Every integer greater than 1 can be written as a product of prime factors. This is unique (Fundamental Theorem of Arithmetic).

Factor tree method

1

Split into any two factors

Divide the number by the smallest prime that goes into it.

2

Keep splitting until all branches are prime

Circle each prime number as you reach it.

3

Write as a product of primes

Collect all circled primes, smallest first. Use index notation.

Example — prime factor decomposition of 360

Divide repeatedly by primes360 = 2×180 = 2×2×90 = 2×2×2×45 = 2×2×2×3×15 = 2×2×2×3×3×5
In index notation360 = 2³ × 3² × 5

Using prime factors to find HCF and LCM

Find HCF and LCM of 360 and 252.

360 = 2³ × 3² × 5    252 = 2² × 3² × 7

HCF — take LOWEST power of each shared primeShared primes: 2 and 3. HCF = 2² × 3² = 4 × 9 = 36
LCM — take HIGHEST power of each primeAll primes: 2,3,5,7. LCM = 2³ × 3² × 5 × 7 = 8×9×5×7 = 2520
HCF uses lowest powers. LCM uses highest powers. This is the most reliable method for large numbers — much better than listing factors.

Learning Objectives

Tick each off as you go.

Expressions & Like Terms

Like terms share the same variable and power. Only like terms can be added or subtracted.

Notation rules

  • 3 × x → write 3x (not 3 × x)
  • x × x → write x²
  • 1 × x → write x (not 1x)
  • x ÷ 2 → write x/2

Collecting like terms

Like terms: same variable AND same power3x + 5x = 8x   4x² − x² = 3x²   2xy + 7xy = 9xy

Example: 5x + 3y − 2x + 4y = 3x + 7y

Example: 4a² + 3a − a² + 2 − 5a = 3a² − 2a + 2

Substitution

Replace letters with given values — then apply BIDMAS carefully.

Method

1

Write the expression

Copy it out before substituting.

2

Replace each letter — use brackets for negatives

If x = −3, write (−3) not just −3.

3

Calculate with BIDMAS

Brackets → Indices → ÷× → +−

Examples

Find 3x² − 2x + 5 when x = 4.

Substitute3(4)² − 2(4) + 5 = 3(16) − 8 + 5 = 48 − 8 + 5 = 45

Find 2a − b when a = 3, b = −5.

Substitute2(3) − (−5) = 6 + 5 = 11

Expanding Brackets

Multiply every term inside the bracket by the term outside.

Single brackets

a(b + c) = ab + ac3(x + 4) = 3x + 12   5x(2x − 3) = 10x² − 15x

Double brackets — FOIL (First, Outer, Inner, Last)

(x + 3)(x + 5)= x² + 5x + 3x + 15 = x² + 8x + 15

(2x − 1)(x + 4) = 2x² + 8x − x − 4 = 2x² + 7x − 4

(x − 3)² = x² − 6x + 9

Difference of two squares

(a + b)(a − b) = a² − b²(x + 5)(x − 5) = x² − 25

Factorising

The reverse of expanding — take out the HCF and write the remainder in a bracket.

Simple factorising

Find HCF of all terms, then divide6x + 9 → HCF = 3 → 3(2x + 3)

12x² − 8x → HCF = 4x → 4x(3x − 2)

Quadratic factorising — x² + bx + c

Find two numbers: multiply to c, add to bx² + 7x + 12 → 3 × 4 = 12, 3 + 4 = 7 → (x + 3)(x + 4)

x² − 5x + 6 → pairs: −2 and −3 → (x − 2)(x − 3)

x² + x − 12 → pairs: 4 and −3 → (x + 4)(x − 3)

Difference of two squares

a² − b² = (a + b)(a − b)x² − 25 = (x + 5)(x − 5)

Substitution Calculator

Evaluates ax² + bx + c for any value of x.

Substitution Calculator

ax² + bx + c — enter coefficients and x

Result
Enter coefficients and x.

Practice

Q1 — Simplify

Simplify 4x² + 3x − x² − 7x

Q2 — Substitution

Find 2x² − 3x when x = −2

Q3 — Factorise

Factorise x² + 2x − 15

Exam Tips

01

Brackets for negative substitution

x=−3: write (−3)²=9, not −3²=−9. The bracket is essential.

02

Check factorising by expanding back

Always expand your factorised answer to check it matches the original.

03

Take out the full HCF

12x²−8x: take out 4x, not just 2 or 4. Get the highest factor of all terms.

04

x² and x are not like terms

Do not add them together. They must be kept separate.

05

FOIL for double brackets

First, Outer, Inner, Last — then collect the middle two terms.

06

Spot difference of two squares

a²−b² = (a+b)(a−b). Look for this pattern before trying other methods.

Learning Objectives

Tick each off as you go.

Area & Perimeter Formulas

Every formula — the height must always be the perpendicular height, not a slant side.

Perimeter

RectangleP = 2(l + w)
Any polygonP = sum of all sides

Area formulas

RectangleA = l × w
TriangleA = ½ × b × h (perpendicular h)
ParallelogramA = b × h (perpendicular h)
TrapeziumA = ½(a + b) × h (a, b = parallel sides)
CircleA = πr²    Circumference = 2πr

Area unit conversions

Length factor squared1 m² = 10 000 cm²   1 cm² = 100 mm²

Converting m² to cm²: multiply by 10 000 (not 100).

Perpendicular height only. The h in every area formula is the height at 90° to the base. The slant side of a triangle is not the height.

Area & Perimeter Calculator

Select a shape, enter dimensions, and see area and perimeter with full working.

Area & Perimeter Calculator

Results
Select a shape and enter dimensions.

Composite Shapes

Split into simpler shapes, calculate each part, then add or subtract.

Method

1

Split into standard shapes

Draw lines on the diagram to divide into rectangles, triangles, etc.

2

Find missing dimensions

Use the total dimensions to calculate unlabelled sides.

3

Calculate each area separately

Apply the correct formula to each simpler shape.

4

Add or subtract

Add parts that make up the shape. Subtract any removed sections.

Example — L-shape

Outer rectangle: 8m × 6m. Corner removed: 3m × 4m.

Subtract method8×6 − 3×4 = 48 − 12 = 36 m²

Practice

Q1 — Trapezium

A trapezium has parallel sides 8 cm and 12 cm, height 5 cm. Find the area.

Q2 — Triangle area

Triangle: base 10 cm, perpendicular height 7 cm. Find the area.

Exam Tips

01

Perpendicular height only

h in every formula = height at 90° to base. Never use the slant.

02

Units and units²

Perimeter in cm/m. Area in cm²/m². Wrong units cost marks.

03

Area conversions: square the factor

m²→cm²: ×10 000. km²→m²: ×1 000 000.

04

Label composite split clearly

Show each sub-area separately. Examiners award marks for method.

05

Find missing sides before perimeter

Work out unlabelled sides using total dimensions before adding up.

06

Trapezium: add parallel sides first

½(a+b)h — add a and b before multiplying. Very common error.

Learning Objectives

Tick each off as you go.

Mean, Median, Mode & Range

The four measures

MeanMean = sum of values ÷ number of values
MedianThe middle value when ordered. Position = (n+1)÷2
ModeThe most frequent value
RangeRange = largest − smallest (measures spread)

Example: 3, 7, 4, 7, 2, 9, 7

Ordered: 2, 3, 4, 7, 7, 7, 9   (n=7)

Mean(2+3+4+7+7+7+9) ÷ 7 = 39 ÷ 7 = 5.57
MedianPosition 4 → 7
Mode7 (appears 3 times)
Range9 − 2 = 7

When to use each average

AverageBest used whenAffected by outliers?
MeanData is fairly symmetricalYes — most affected
MedianData has outliers or is skewedNo
ModeCategorical or discrete dataNo

Averages from Tables

Frequency table — exact values

Multiply each value by its frequency, sum the products, divide by total frequency.

Score (x)Frequency (f)f × x
133
2510
326
Totals1019
Mean19 ÷ 10 = 1.9

Grouped frequency table — estimated mean

Use the midpoint of each class. This gives an estimate, not an exact answer.

ClassMidpoint (m)Freq (f)f × m
0–105420
10–2015690
20–3025250
Totals12160
Estimated mean160 ÷ 12 = 13.3   Modal class = 10–20

Averages Calculator

Enter a list of numbers separated by commas.

Mean, Median, Mode & Range Calculator

Results
Enter your data above.

Practice

Q1 — Median

Find the median of: 5, 2, 8, 1, 9, 4, 3

Q2 — Mean from table

Value 2 occurs 4 times, value 3 occurs 6 times, value 4 occurs 2 times. Find the mean.

Exam Tips

01

Always order before finding median

The most common error. Write the ordered list before identifying the middle.

02

Even number of values

8 values → median = average of 4th and 5th. Add and divide by 2.

03

Mean from table: Σfx ÷ Σf

Divide by total frequency, not number of rows. Very common error.

04

Grouped: use midpoints and call it an estimate

Write "estimated mean" — the answer cannot be exact from grouped data.

05

Range ≠ average

Range measures spread. Never call it an average.

06

Comparing: use both average and spread

Always comment on the average and the range when comparing two distributions.

Learning Objectives

Tick each off as you go.

Where this fits

Algebra strand, Foundation and Higher. Function machines appear on both calculator and non-calculator papers. Inverse and composite functions are mainly Higher. Function notation f(x) is expected at both tiers.

What are Function Machines?

A function machine takes an input, applies one or more operations in sequence, and produces an output.

The idea — a factory conveyor belt

Think of each operation as a station on a conveyor belt. Whatever goes in one end comes out the other end changed by each station in turn.

Input: 4
× 3
12
+ 5
Output: 17

This machine applies ×3 then +5. In function notation: f(x) = 3x + 5. When x = 4: f(4) = 17.

Function notation f(x)

f(x) = output when x is the inputf(x) = 2x − 1    f(5) = 2(5) − 1 = 9

Different letters are used — f(x), g(x), h(x) — but they all work the same way. f(3) means "apply the function to 3", not f multiplied by 3.

Multi-step machines

Always apply operations left to right in the order given. Do not rearrange or skip steps.

Machine: ÷ 2 then + 7 then × 3. Input = 10.10 ÷ 2 = 5 → 5 + 7 = 12 → 12 × 3 = 36

Inverse Functions

The inverse function undoes what the original did — it maps outputs back to inputs. Run the machine backwards with opposite operations.

Inverse operations

OperationInverse
+ a− a
× a÷ a
− a+ a
÷ a× a
√x
∛x

Finding the inverse algebraically

1

Write y = f(x)

Replace f(x) with y.

2

Rearrange to make x the subject

Apply inverse operations — reverse the order of the original steps.

3

Write as f⁻¹(x)

Swap x and y in your rearranged equation.

Example — find f⁻¹(x) for f(x) = 3x − 7

Step 1: y = 3x − 7Step 2: y + 7 = 3x → x = (y + 7) ÷ 3
Step 3: f⁻¹(x) = (x + 7) ÷ 3
Check: f(5) = 3(5)−7 = 8. Then f⁻¹(8) = (8+7)÷3 = 5. ✓ Got back to the original input.
Reverse the order of operations. f(x) = 3x − 7 does ×3 first then −7. The inverse does +7 first then ÷3 — the order flips as well as the operations.

Interactive Function Machine

Build a two-step machine. Enter an input to find the output, or enter an output to work backwards and find the input.

Function Machine Builder

Choose two operations — run forwards or backwards

Build your machine

Results
Build your machine above and enter a value.
Try it: Set Step 1 = ×3, Step 2 = +5. Enter input 4 → output should be 17. Then enter output 17 → the inverse should give back 4.

Composite Functions — Higher

A composite function applies one function to the result of another. fg(x) means apply g first, then f.

Notation and order

fg(x) = f(g(x)) — g first, then ff(x) = x + 3, g(x) = 2x
fg(x) = f(g(x)) = f(2x) = 2x + 3
gf(x) = g(f(x)) — f first, then ggf(x) = g(f(x)) = g(x+3) = 2(x+3) = 2x + 6
fg ≠ gf in general. Order matters. Always apply the function closest to x first.

Evaluating a composite — step by step

f(x) = x² + 1, g(x) = 3x. Find fg(4).

Step 1: apply g to 4g(4) = 3 × 4 = 12
Step 2: apply f to the resultf(12) = 12² + 1 = 144 + 1 = 145

Finding the composite as an expression

f(x) = 2x − 1, g(x) = x + 4. Find fg(x) as an expression.

Substitute g(x) into ffg(x) = f(x+4) = 2(x+4) − 1 = 2x + 8 − 1 = 2x + 7

Practice

Q1 — Output

A function machine applies ×4 then −3. What is the output when the input is 7?

Q2 — Inverse

f(x) = 5x + 2. Find f⁻¹(x).

Q3 — Inverse machine

A machine does ×2 then +6. An output is 20. What was the input?

Q4 — Composite (Higher)

f(x) = x + 3 and g(x) = 2x. Find fg(5).

Exam Tips

01

Apply operations left to right

Function machines work in sequence. Do not change the order of operations.

02

Inverse: reverse operations AND order

f(x) = ×3 then +5. Inverse = −5 first, then ÷3. Both the operation and the sequence flip.

03

Always verify your inverse

Apply f then f⁻¹ — you should get back to the original input. If not, recheck.

04

fg(x): g first, then f

The function closest to x is applied first. fg(x) = f(g(x)), not g(f(x)).

05

f(3) is a value, not f × 3

Function notation means "evaluate f at x=3". It is not multiplication.

06

Show intermediate values

For multi-step machines, write the value after each step. Examiners award method marks for this.

Learning Objectives

Tick each off as you go.

Formula sheet reminder

At GCSE you are given: Volume of cone = ⅓πr²h, Volume of sphere = ⁴⁄₃πr³, Surface area of sphere = 4πr². You are NOT given cylinder, cuboid or prism formulas — these must be memorised.

Arc Length & Sector Area

An arc is a fraction of the circumference. A sector is a pizza-slice fraction of the full circle.

The key idea

Both formulas work the same way: take the fraction of the full circle (angle ÷ 360), then multiply by the full circle formula.

Arc lengthL = (θ ÷ 360) × 2πr
Sector areaA = (θ ÷ 360) × πr²

θ = angle of the sector in degrees. Both are just a fraction of the full circle formula.

Worked example — radius 6 cm, angle 120°

Arc length(120÷360) × 2π×6 = ⅓ × 12π = 4π ≈ 12.57 cm
Sector area(120÷360) × π×6² = ⅓ × 36π = 12π ≈ 37.70 cm²

Perimeter of a sector

Perimeter = arc length + 2 radiiP = L + 2r

Using the example above: P = 4π + 2(6) = 4π + 12 ≈ 24.57 cm

Common error: forgetting to add the two radii when asked for the perimeter of a sector. The arc length alone is not the full perimeter.

Volume

Volume measures how much 3D space a shape occupies. Units are always cubed (cm³, m³).

All volume formulas

Prism (any cross-section)V = area of cross-section × length
CylinderV = πr²h — memorise this
ConeV = ⅓πr²h — on formula sheet
SphereV = ⁴⁄₃πr³ — on formula sheet
Pyramid (any base)V = ⅓ × base area × height
CuboidV = l × w × h

Volume of a prism — identifying the cross-section

A prism is any 3D shape with a constant cross-section running along its length. The key step is identifying the 2D cross-section shape and finding its area first.

  • Triangular prism: cross-section is a triangle → A = ½bh, then × length
  • Cylinder: cross-section is a circle → A = πr², then × height
  • L-shaped prism: cross-section is an L-shape → split into rectangles, add areas, then × length
Volume units: if lengths are in cm, volume is in cm³. If in m, volume is m³. Never mix units within one calculation.

Surface Area

Surface area is the total area of all faces of a 3D shape. Add the area of every face — do not miss any.

All surface area formulas

CuboidSA = 2(lw + lh + wh)
CylinderSA = 2πr² + 2πrh (two circles + curved rectangle)
ConeSA = πr² + πrl (base circle + curved surface, l = slant height)
SphereSA = 4πr² — on formula sheet

Cone — slant height vs vertical height

If only vertical height h is given, find slant height l firstl = √(r² + h²) (Pythagoras)

Surface area of cone uses slant height l. Volume of cone uses vertical height h. These are different values.

Open vs closed shapes

Check whether the question asks for a closed shape (all faces) or an open shape (e.g. a cup with no base, or a half-sphere on a cylinder). Only include the faces that are part of the surface.

  • Closed cylinder: 2πr² + 2πrh (both circular ends + curved surface)
  • Open cylinder (no lid): πr² + 2πrh (one circular base + curved surface)
Surface area units are cm², m² etc. — not cm³. A very common error is giving the surface area in cubic units.

3D Shape Calculator

Select a shape, enter its dimensions, and see volume and surface area with full working shown.

Volume & Surface Area Calculator

Cylinder, cone, sphere, cuboid, triangular prism

Results
Select a shape and enter dimensions.
Try it: Cylinder with r = 5, h = 10. Volume = π×25×10 = 250π ≈ 785.4 cm³. Surface area = 2π×25 + 2π×5×10 = 50π + 100π = 150π ≈ 471.2 cm².

Practice

Use π where needed — give exact answers in terms of π unless told otherwise.

Q1 — Cylinder volume

A cylinder has radius 4 cm and height 9 cm. Find the volume in terms of π.

Q2 — Sphere surface area

Find the surface area of a sphere with radius 5 cm. Give answer in terms of π.

Q3 — Sector area

A sector has radius 9 cm and angle 80°. Find the area. Give answer to 3 significant figures.

Q4 — Cone surface area

A cone has radius 3 cm and vertical height 4 cm. Find the total surface area in terms of π.

Exam Tips

01

Cone and sphere formulas are on the sheet

You must memorise cylinder (πr²h) and cuboid (lwh). Cone and sphere are given.

02

Cone: slant height ≠ vertical height

SA uses slant height l. Volume uses vertical height h. Find l = √(r²+h²) when needed.

03

Leave answers in terms of π when asked

24π is exact. 75.4 is not. Many mark schemes require the exact form.

04

Prisms: identify the cross-section first

V = cross-section area × length. Identify the 2D shape, find its area, then multiply.

05

Sector perimeter = arc + 2 radii

Do not give just the arc length when asked for the perimeter of a sector.

06

Surface area units: cm², not cm³

Volume in cm³. Surface area in cm². Wrong units cost marks every time.

Learning Objectives

Tick each off as you go.

Where this fits

Geometry and Measures — Higher tier mainly, though basic column vectors appear at Foundation. Vector proof questions are exclusively Higher and are often worth 4–5 marks. They test whether you can navigate a diagram systematically.

Introduction to Vectors

A vector has both magnitude (size) and direction. A scalar has magnitude only.

Vectors vs scalars

Scalar (magnitude only)Vector (magnitude + direction)
Speed: 30 mphVelocity: 30 mph due north
Distance: 5 kmDisplacement: 5 km east
Mass: 70 kgForce: 70 N downwards
Temperature: 20°CAcceleration: 9.8 m/s² downwards

Column vector notation

Written as x on top, y below in brackets (3 above, 2 below) means 3 right and 2 up
(−1 above, 4 below) means 1 left and 4 up
(0 above, −3 below) means 3 down (no horizontal movement)

Positive x → right   Negative x → left   Positive y → up   Negative y → down

Naming and writing vectors

  • Bold lettera, b (used in textbooks and exam papers)
  • Underlineda (used in handwriting — always underline in your answers)
  • Arrow over two letters — AB⃗ means the vector from point A to point B
  • Negative vector — −a has the same magnitude as a but points in the opposite direction
  • Equal vectors — two vectors are equal if they have the same magnitude and direction, regardless of position
A vector has no fixed position. It only describes a movement. Two arrows of the same length pointing the same way represent the same vector, even if drawn in different places on a diagram.

Vector Operations

All operations work component by component — x with x, y with y.

Adding vectors

Add x-components and y-components separately (3 above, 2 below) + (1 above, 5 below) = (4 above, 7 below)

Geometrically: place the second vector at the tip of the first. The sum goes from the start of the first to the end of the second.

Example: a = (4, −2), b = (−1, 5) a + b = (4 + (−1), −2 + 5) = (3, 3)

Subtracting vectors

Subtract component by component — same as adding the negative a − b = a + (−b)
Example: a = (5, 3), b = (2, 7) a − b = (5 − 2, 3 − 7) = (3, −4)

Scalar multiplication

Multiply every component by the scalar 3 × (2 above, −1 below) = (6 above, −3 below)
½ × (4 above, 8 below) = (2 above, 4 below)

A positive scalar scales the magnitude but keeps the direction. A negative scalar also reverses the direction. A scalar of −1 gives the negative vector.

Parallel vectors

Two vectors are parallel if one is a scalar multiple of the other.

Example a = (2, 6)   b = (1, 3)   Since a = 2b, they are parallel

If two vectors share a common point and are parallel, then the three points are collinear (lie on a straight line).

Magnitude of a Vector

The magnitude is the length of the vector — calculated using Pythagoras' theorem.

Formula

For vector (x above, y below)|v| = √(x² + y²)

The vertical bars | | mean "magnitude of". This is exactly Pythagoras applied to the horizontal and vertical components.

Examples

Vector (3, 4)|v| = √(3² + 4²) = √(9 + 16) = √25 = 5
Vector (5, 12)|v| = √(5² + 12²) = √(25 + 144) = √169 = 13
Vector (−3, 4)|v| = √((−3)² + 4²) = √(9 + 16) = √25 = 5

Notice: (3, 4) and (−3, 4) have the same magnitude even though they point in different directions. Magnitude is always positive.

Pythagorean triples to remember: 3-4-5, 5-12-13, 8-15-17. These come up regularly in vector magnitude questions on non-calculator papers.

Unit vectors

A unit vector has magnitude 1. To find the unit vector in the direction of v:

Unit vectorv̂ = v ÷ |v|

Example: v = (3, 4), |v| = 5. Unit vector = (3/5, 4/5) = (0.6, 0.8).

Vector Paths — Higher

Vector path problems ask you to find the vector for a route by combining known vectors. The key rule: going against an arrow negates the vector.

The golden rule

Route from A to C via BAC⃗ = AB⃗ + BC⃗
Going backwards against arrow ABBA⃗ = −AB⃗ = −a

Build up any path step by step. Each step either uses a vector directly (going with the arrow) or negates it (going against the arrow).

Worked example

OA⃗ = a, OB⃗ = b. M is the midpoint of AB. Find OM⃗.

Step 1: find AB⃗AB⃗ = AO⃗ + OB⃗ = −a + b = ba
Step 2: AM⃗ = ½AB⃗ (M is midpoint)AM⃗ = ½(ba)
Step 3: route O → A → MOM⃗ = OA⃗ + AM⃗ = a + ½(ba) = a + ½b − ½a = ½a + ½b

Proving collinearity

To prove three points P, Q, R are collinear:

1

Find PQ⃗ and PR⃗ (or QR⃗)

Express both in terms of the given vectors.

2

Show one is a scalar multiple of the other

e.g. PR⃗ = 2PQ⃗ means they are parallel.

3

State they share a common point

Since PQ and PR both pass through P and are parallel, P, Q and R are collinear.

Must state the shared point. Showing two vectors are parallel is not enough — you must also state they share a common point to conclude the three points are collinear.

Vector Calculator

Enter two vectors — the calculator shows all combinations with full working.

Vector Calculator

Enter components for vectors a and b

Vector a = (x, y)

Vector b = (p, q)

Results
Enter vector components above.
Try it: Enter a = (3, 4) and b = (5, 12). The magnitudes are 5 and 13 — both Pythagorean triples. a + b = (8, 16). Are a and b parallel? Check if one is a scalar multiple of the other.

Practice

Q1 — Adding vectors

a = (4, −2) and b = (−1, 5). Find a + b.

Q2 — Magnitude

Find the magnitude of vector (5, 12).

Q3 — Scalar multiplication

a = (2, −5). Find 3a.

Q4 — Vector paths (Higher)

OA⃗ = a and OB⃗ = b. M is the midpoint of OB. Find AM⃗.

Exam Tips

01

Add/subtract component by component

Top + top, bottom + bottom. Never mix x and y components.

02

Magnitude uses Pythagoras

|v| = √(x²+y²). Square each component separately before adding — never add then square.

03

Going backwards negates the vector

If OA⃗ = a, then AO⃗ = −a. Travelling against the arrow direction means negate all components.

04

Underline vectors in handwriting

Write a not just a. Examiners distinguish between vectors and scalars.

05

Parallel vectors are scalar multiples

If b = 3a, the vectors are parallel. Use this to prove collinearity.

06

Collinearity needs parallel + shared point

Proving two vectors are parallel is not enough. You must also state they share a common point.

07

Build paths step by step

Write each step of the route separately. AC⃗ = AB⃗ + BC⃗. Systematic working earns all marks even if the algebra gets complex.

08

Memorise Pythagorean triples

3-4-5, 5-12-13, 8-15-17 appear constantly in magnitude questions on non-calculator papers.

Learning Objectives

Tick each off as you go.

Where this fits

Statistics strand — Foundation and Higher. Chart reading and drawing appears on both papers. Scatter graphs with correlation descriptions are very common. Frequency polygons and back-to-back stem and leaf diagrams appear more often on Higher.

Chart Types

Each chart has a specific purpose. Using the wrong type — or misreading one — is a common error.

Summary of chart types

ChartBest used forKey reading rule
Bar chartComparing discrete categoriesHeight of bar = frequency
Dual bar chartComparing two groups across categoriesRead each bar separately, compare side by side
Line graphChange over time (continuous)Read from the line — gradient shows rate of change
PictogramSimple frequency — visual appealOne symbol = fixed number — ALWAYS check the key
Pie chartProportions of a wholeAngle ÷ 360 × total = frequency
Frequency polygonGrouped continuous dataPlot at midpoints, join with straight lines
Scatter graphRelationship between two variablesLine of best fit — read from line not from points
Stem and leafRaw data — shows distribution shapeLeaves increase away from stem

Common reading errors

  • Bar chart: reading the label rather than the top of the bar
  • Pictogram: treating every symbol as 1 — always check the key first
  • Line graph: reading between gridlines — use a ruler for accuracy
  • Pie chart: estimating angles — use the formula, not guesswork
  • Scatter graph: reading from a data point rather than the line of best fit

Scatter Graphs

Scatter graphs show whether two variables are related. Each point represents one item with two measurements.

Types of correlation

TypeWhat the graph looks likeReal example
Strong positivePoints close to an upward lineHeight and shoe size
Weak positiveRoughly upward trend, spread outRevision hours and exam score
Strong negativePoints close to a downward lineSpeed and journey time
Weak negativeRoughly downward, spread outTemperature and hot drink sales
No correlationNo pattern — points scattered randomlyShoe size and exam score

Drawing a line of best fit

  • Draw a single straight line through the middle of the data points
  • Aim for roughly equal numbers of points above and below the line
  • The line does not have to pass through the origin or any specific point
  • The line should follow the overall trend — ignore outliers
  • Use a ruler — a freehand line will lose marks

Using the line of best fit

Interpolation — estimating within the data rangeDraw a vertical line from the x-value to the line, then read across to the y-axis

Only interpolate — do not extrapolate far beyond the range of the data. The relationship may not continue outside the range you measured.

Correlation vs causation

Correlation means two variables tend to change together. Causation means one variable directly causes the other to change. Correlation does not prove causation.

Classic example: Ice cream sales and drowning incidents both increase in summer. They are correlated — but eating ice cream does not cause drowning. Both are caused by hot weather (a lurking variable).

Exam phrasing: never write "A causes B" based on a scatter graph. Write "there is a [strong/weak] [positive/negative] correlation between A and B."

Describing an outlier

An outlier is a point that does not fit the general trend. In an exam question, identify it by its approximate coordinates and explain that it does not follow the pattern shown by the other data points.

Frequency Polygons

Used for grouped continuous data. Plot the midpoint of each class against its frequency, then join with straight lines.

Drawing a frequency polygon — step by step

1

Find the midpoint of each class

Midpoint = (lower boundary + upper boundary) ÷ 2. For 10 ≤ x < 20: midpoint = (10+20)÷2 = 15.

2

Plot each point (midpoint, frequency)

Midpoint on the x-axis, frequency on the y-axis.

3

Join all points with straight lines

Use a ruler. Do not use a curve. Do not extend the line back to zero at either end (unless the question asks you to close the polygon).

4

Label your axes and give a title

Missing labels cost marks.

Worked example

Class (age)FrequencyMidpointPlot point
0 ≤ x < 1045(5, 4)
10 ≤ x < 20915(15, 9)
20 ≤ x < 301225(25, 12)
30 ≤ x < 40735(35, 7)
40 ≤ x < 50345(45, 3)

Plot the five points and join with four straight line segments.

Comparing two frequency polygons

When two polygons are drawn on the same axes, you can compare their distributions directly. In exam answers, comment on:

  • Which group has the higher peak (modal class)
  • Which group is more spread out (wider polygon = more variation)
  • Whether one group is skewed towards higher or lower values

Stem and Leaf Diagrams

Show the actual data values while also displaying the distribution shape. Every value is preserved.

Reading a stem and leaf diagram

The stem is the tens digit. Each leaf is a units digit. Leaves are written in order, smallest closest to the stem.

Stem | Leaves (units digits)
1 | 2 4 7 9
2 | 0 3 3 6 8
3 | 1 5 5 7
4 | 2 6
Key: 1 | 2 represents 12

From this diagram: min = 12, max = 46, range = 34, median = 28 (8th of 15 values), mode = 23 and 35.

Back-to-back stem and leaf

Compares two groups using a shared stem in the middle. Leaves for Group A go left, leaves for Group B go right.

Group A | Stem | Group B
9 7 4 2|1|3 5 8
8 6 3 1 0|2|0 2 4 7
5 2|3|1 6 9
Key: 4|1 = 14 (Group A)   1|3 = 13 (Group B)
Group A leaves are read right to left (smallest closest to stem). Group B reads left to right as normal.

Finding averages from stem and leaf

  • Median: count the total values, find the middle position, read the value directly from the diagram
  • Mode: the leaf that appears most often on the same stem
  • Range: largest value − smallest value (read from ends of diagram)
  • Mean: list all values, sum them, divide by n

Interactive Scatter Plotter

Enter data points to plot a scatter graph, see the correlation described, and draw an automatic line of best fit.

Scatter Graph Plotter

Enter x,y pairs — one per line (e.g. 3,7)

Correlation
Enter data points above.
Try it: The default data shows revision hours vs exam scores — a strong positive correlation. Change the data and watch the correlation description update. Try adding an outlier (e.g. 9,20) and see how it affects the line of best fit.

Practice

Q1 — Correlation

A scatter graph shows that as temperature increases, the number of coats sold decreases. Which best describes this?

Q2 — Frequency polygon

For the class 20 ≤ x < 30 with frequency 8, where is the point plotted on a frequency polygon?

Q3 — Stem and leaf

A stem and leaf diagram has: 1 | 3 5 8, 2 | 0 4 7, 3 | 2 6. Key: 1|3 = 13. What is the median?

Q4 — Correlation vs causation

A scatter graph shows a strong positive correlation between shoe size and reading ability in children. What can we conclude?

Exam Tips

01

Correlation ≠ causation

Never say one variable causes another based on a scatter graph. Always use "correlation" language.

02

Line of best fit: balance above and below

Equal numbers of points above and below. Use a ruler. It does not need to pass through any specific point.

03

Frequency polygon: midpoints only

Never plot at the class boundary. Always calculate (lower + upper) ÷ 2 first.

04

Describe correlation with strength AND direction

"Strong negative correlation" earns more marks than just "negative." Both words count.

05

Check pictogram keys before counting

One symbol might equal 5, 10 or any number. Reading the key is the first step, not the last.

06

Stem and leaf: order the leaves

Leaves must be written in order (smallest nearest the stem). Disordered leaves lose marks.

07

Back-to-back: Group A reads right to left

The left side of a back-to-back diagram increases away from the stem, not towards it.

08

Do not extrapolate beyond the data

Using a line of best fit beyond the measured range gives unreliable estimates. State this limitation when asked.

Learning Objectives

Tick each off as you go.

Where this fits

Probability and Statistics — Foundation and Higher. Two-circle diagrams appear on both tiers. Three-circle diagrams and the addition rule are Higher. Venn diagrams often link to frequency trees, two-way tables and conditional probability.

Sets & Notation

A set is a collection of objects. In GCSE we deal with numbers or events.

Key symbols

SymbolNameMeaningExample
ξUniversal setEverything being consideredIntegers 1–10
A∪BUnionIn A OR B (or both)Evens or multiples of 3
A∩BIntersectionIn A AND BEven multiples of 3: {6}
A'ComplementNOT in AOdd numbers: {1,3,5,7,9}
n(A)CardinalityNumber of elements in An(A)=5 means 5 elements
Empty setNo elementsA∩B=∅ means no overlap
Memory trick: ∪ looks like a U for Union (OR). ∩ looks like an n for iNtersection (AND).

Reading notation

A∪B — Union (OR)All elements in A, in B, or in both — the full shaded area of both circles.
A∩B — Intersection (AND)Only elements in both A and B — the overlapping region only.
A' — Complement (NOT A)Everything in ξ that is NOT in A — outside the A circle.
(A∪B)' — NeitherEverything outside both circles — in neither set.

Two-Circle Venn Diagrams

Four regions: A only, the overlap (A∩B), B only, and outside both. Always start with the intersection.

The four regions

A only not in B A∩B both B only not in A ξ neither

Method — start with the intersection

1

Fill in A∩B first

The intersection goes in the overlap. This is usually given or stated as "both".

2

A only = n(A) − intersection

Subtract what is already in the overlap from the total in A.

3

B only = n(B) − intersection

Same idea for B.

4

Outside = n(ξ) − all inside

Subtract the sum of all three inner regions from the total.

Worked example

30 students. 18 study French (F), 12 study Spanish (S), 7 study both. Find all regions.

RegionCalculationValue
F∩S (both)Given directly7
F only18 − 711
S only12 − 75
Neither30 − (11+7+5)7
Check: 11 + 7 + 5 + 7 = 30 ✓ Always verify the total equals n(ξ).

Three-Circle Venn Diagrams — Higher

Seven regions plus the outside. Always work from the centre outwards.

The regions

A only B only C only A∩B A∩C B∩C A∩B∩C ξ

Method — centre outwards

1

Place A∩B∩C first

The centre value. Always start here.

2

Each pair's exclusive overlap

e.g. A∩B only = (A∩B) − (A∩B∩C). Subtract the centre from each pair total.

3

Each circle's exclusive region

A only = n(A) − (A∩B only) − (A∩C only) − (A∩B∩C).

4

Outside = n(ξ) − all inside

Subtract the sum of all seven inner regions.

Probability from Venn Diagrams

Once the diagram is complete, read probabilities from the regions.

Key probability formulas

Basic probabilityP(A) = n(A) ÷ n(ξ)
Intersection — ANDP(A∩B) = overlap ÷ n(ξ)
Union — OR — Addition RuleP(A∪B) = P(A) + P(B) − P(A∩B)
Complement — NOTP(A') = 1 − P(A)
Conditional — HigherP(A|B) = P(A∩B) ÷ P(B)

Using the French/Spanish example

F only=11, F∩S=7, S only=5, Neither=7. Total n(ξ)=30.

ProbabilityCalculationAnswer
P(F)(11+7) ÷ 3018/30 = 3/5
P(F∩S)7 ÷ 307/30
P(F∪S)18/30+12/30−7/3023/30
P(F')1 − 18/3012/30 = 2/5
P(neither)7 ÷ 307/30
P(F|S) HigherP(F∩S) ÷ P(S) = (7/30)÷(12/30)7/12
Addition rule — do not double count. P(A)+P(B) counts the intersection twice. Always subtract P(A∩B) once.

Mutually exclusive events

A∩B = ∅ — circles do not overlapP(A∪B) = P(A) + P(B) — no need to subtract

Interactive Venn Builder

Enter counts for each region — the diagram and all probabilities update live.

Venn Diagram Builder

Two-circle diagram — enter counts for each region

Probabilities
Enter values above to see probabilities.
Try it: Default values show the French/Spanish example. Change the values and watch everything update live.

Practice

Q1 — Notation

What does A∩B represent?

Q2 — Completing the diagram

50 people surveyed. 28 like coffee, 19 like tea, 11 like both. How many like neither?

Q3 — Union probability

Using the coffee/tea data (50 people, coffee=28, tea=19, both=11). Find P(coffee ∪ tea).

Q4 — Complement

P(A) = 0.45. What is P(A')?

Exam Tips

01

Start with the intersection

Fill A∩B first. Then A only=n(A)−intersection. B only=n(B)−intersection.

02

Check your total equals n(ξ)

Add all four regions. If they do not sum to n(ξ), recheck every step.

03

∪ means OR — include all three inner regions

P(A∪B) = A only + overlap + B only. Do not forget the overlap is shared.

04

Addition rule — subtract the intersection

P(A∪B)=P(A)+P(B)−P(A∩B). Forgetting to subtract is the most common error.

05

Three circles — work centre outwards

Start A∩B∩C, then each pair's exclusive overlap, then each circle's exclusive region, then outside.

06

Label all regions — even zeros

Write 0 in empty regions. Blank regions look like mistakes and lose marks.

07

∩ = AND, ∪ = OR

Confusing these reverses the answer. Memorise both symbols before the exam.

08

Conditional P(A|B) — Higher

P(A|B)=P(A∩B)÷P(B). The denominator is P(B) — you are restricted to set B.

Learning Objectives

Tick each off as you go.

Where this fits

Statistics — Foundation and Higher, both papers. Frequency tables are a foundation skill that feeds into averages, probability, histograms and cumulative frequency. Two-way tables appear on almost every paper.

Tally Charts

A tally chart records data as it is collected. Each mark represents one item. Every fifth mark crosses the previous four — making counting in fives easy.

How tallying works

ColourTallyFrequency
Red|||| |||| |11
Blue|||| ||||9
Green|||| |||8
Total28

The diagonal crossing stroke on every 5th tally makes counting efficient. Always count in groups of five when reading tallies.

From raw data to tally chart

1

List all possible categories or values

Write them in the left column before you start recording.

2

Go through the data one item at a time

Mark one tally stroke for each item in the correct row.

3

Count tallies and write the frequency

Count in fives. Write the total in the Frequency column.

4

Check: frequencies sum to total n

Add all frequencies. They must equal the total number of items.

Ungrouped Frequency Tables

Data recorded as exact values. You can find all four averages directly from the table.

Finding averages — the fx method

MeanMean = Σ(f × x) ÷ Σf

Add a third column (f × x). Sum it. Divide by the total frequency Σf.

Score (x)Frequency (f)f × x
133
2714
3515
4416
515
Total2053
Mean53 ÷ 20 = 2.65

Median from a frequency table

Median position(n + 1) ÷ 2 = (20 + 1) ÷ 2 = 10.5th value

Use a cumulative frequency column to find which value is in position 10 and 11.

ScoreFrequencyCumulative frequency
133
2710
3515
4419
5120

Position 10 → score 2. Position 11 → score 3. Median = (2+3)÷2 = 2.5

Mode = 2 (highest frequency). Range = 5 − 1 = 4

Common error: dividing by the number of rows instead of the total frequency Σf. Always divide by the sum of the frequency column.

Grouped Frequency Tables

Data is placed into class intervals. Exact values are lost — so averages are estimates only.

Estimated mean — use midpoints

Midpoint of a classm = (lower boundary + upper boundary) ÷ 2
Class (height cm)Freq (f)Midpoint (m)f × m
140 ≤ h < 1504145580
150 ≤ h < 160111551705
160 ≤ h < 17091651485
170 ≤ h < 18061751050
Total304820
Estimated mean4820 ÷ 30 = 160.7 cm
Always write "estimated mean" — the exact mean cannot be found from grouped data.

Modal class and median class

Modal classThe class with the highest frequency — 150 ≤ h < 160 (frequency 11)
Median classFind the class containing the middle value — position (30+1)÷2 = 15.5
Cumulative: 4, 15, 24, 30. Position 15.5 falls in 150 ≤ h < 160

Probability from a grouped table

P(value in a class)P = class frequency ÷ total frequency

Example: P(height is 160–170) = 9 ÷ 30 = 3/10 = 0.3

Frequency Table Calculator

Enter your ungrouped frequency table — the calculator finds all averages with full working.

Frequency Table Calculator

Enter values and frequencies — mean, median, mode and range calculated automatically

Enter up to 8 rows. Leave empty rows blank.

Value (x)
Frequency (f)
Results
Enter values and frequencies to calculate averages.
Try it: Enter x = 1,2,3,4,5 with frequencies 3,7,5,4,1 — you should get mean=2.65, median=2.5, mode=2, range=4.

Two-Way Tables

Show two pieces of categorical information simultaneously. Row totals, column totals and the grand total must all be consistent.

Reading a two-way table

CatsDogsNeitherTotal
Boys812525
Girls146525
Total22181050

Row totals and column totals must both sum to the grand total (50). Use this to find missing values.

Finding a missing value

1

Use the totals as equations

Each row and each column must sum to its total. Write these as equations.

2

Substitute known values

Fill in what you know. The missing value is whatever makes the row or column sum correctly.

Probability from a two-way table

Using the cats/dogs table above (50 students total):

QuestionCalculationAnswer
P(likes cats)22 ÷ 5011/25 = 0.44
P(girl who likes dogs)6 ÷ 503/25 = 0.12
P(boy | likes cats)8 ÷ 224/11 ≈ 0.364
P(girl | likes dogs)6 ÷ 181/3 ≈ 0.333
Conditional probability from a table: P(A|B) — restrict to the B column/row total as the denominator, not the grand total.

Practice

Q1 — Mean from frequency table

A frequency table shows: value 2 (freq 3), value 4 (freq 5), value 6 (freq 2). What is the mean?

Q2 — Grouped table

A grouped table has class 20≤x<30 with frequency 8 and class 30≤x<40 with frequency 12. What is the midpoint of the second class?

Q3 — Two-way table

In a two-way table: 40 students total. 22 are girls. 15 boys play sport. 10 girls play sport. How many students play sport in total?

Q4 — Modal class

Classes: 0–10 (f=3), 10–20 (f=12), 20–30 (f=8), 30–40 (f=5). What is the modal class?

Exam Tips

01

Divide by Σf, not number of rows

Mean = Σ(fx) ÷ Σf. Dividing by the number of rows (e.g. 5) instead of total frequency is the most common error.

02

Add the fx column explicitly

Always write out the f×x column. It earns method marks and prevents arithmetic errors.

03

Grouped data: write "estimated mean"

Midpoints are approximations. The word "estimated" is required in your answer.

04

Modal class ≠ mode

For grouped data you can only state the modal class (e.g. 10≤x<20), not a specific mode value.

05

Two-way table: row + column totals must agree

Check every row and column sums to its marginal total. Use this to find missing values.

06

Conditional probability: use row/column total

P(A|B) — the denominator is the B total, not the grand total.

07

Median in frequency table: use cumulative frequency

Add a running total column. Find the row that contains the median position.

08

Always check your total frequency

Sum the frequency column before doing any calculations. A wrong total cascades through everything.

Learning Objectives

Tick each off as you go.

Where this fits

Probability — Foundation and Higher, both papers. Basic probability and expected outcomes are Foundation. Independent events, relative frequency as an estimate, and combining probabilities are Higher. Links to Venn diagrams and tree diagrams (Combined Events lesson).

Basic Probability

Probability measures how likely an event is — always between 0 (impossible) and 1 (certain).

The probability scale

00.250.50.751
ImpossibleUnlikelyEven chanceLikelyCertain

Theoretical probability formula

For equally likely outcomesP(event) = number of favourable outcomes ÷ total number of possible outcomes

Example: rolling a fair die. P(even) = 3/6 = 1/2 (three even numbers: 2, 4, 6 out of six outcomes)

Example: picking a red card from a standard deck. P(red) = 26/52 = 1/2

Complement rule

Probability of event NOT happeningP(A') = 1 − P(A)

Example: P(rain tomorrow) = 0.35. P(no rain) = 1 − 0.35 = 0.65

Listing outcomes systematically

For combined events, list all outcomes in a sample space diagram.

Example: two coins. Outcomes: HH, HT, TH, TT. P(two heads) = 1/4. P(at least one head) = 3/4.

Always list systematically to avoid missing outcomes. Use a table or ordered list.

Experimental Probability

Also called relative frequency — based on actual results from an experiment or survey rather than theory.

Relative frequency formula

Relative frequency (experimental probability)P(event) ≈ number of times event occurred ÷ total number of trials

Example: a biased coin is flipped 200 times. Heads occurs 130 times.

Relative frequency of heads130 ÷ 200 = 0.65

This is an estimate for P(heads). The more trials, the more reliable the estimate.

Theoretical vs experimental probability

TheoreticalExperimental
Based onEqually likely outcomesActual results
When to useFair coins, dice, cardsBiased equipment, real data
Improves withMore outcomes listedMore trials
SymbolP(A) = exact valueP(A) ≈ relative frequency

Bias and fairness

If experimental probability consistently differs from theoretical probability after many trials, the equipment is likely biased.

Example: if a die shows 6 on 1/4 of trials (theoretical = 1/6), it is likely biased towards 6.

More trials = more reliable estimate. With only 10 trials, results vary a lot. With 1000 trials, the relative frequency gets close to the true probability.

Expected Outcomes

Expected frequency predicts how many times an event will occur in a given number of trials.

Formula

Expected frequencyE = probability × number of trials

Example: P(six on a fair die) = 1/6. Roll 300 times. Expected sixes = 1/6 × 300 = 50

Example: P(defective item) = 0.03. Produce 2500 items. Expected defective = 0.03 × 2500 = 75

Working backwards — finding n

If you know the expected frequency and the probability, you can find the number of trials.

n = expected frequency ÷ probabilityExpected heads = 40, P(head) = 0.5 → n = 40 ÷ 0.5 = 80 trials
Expected frequency is not guaranteed. It is a prediction, not a certainty. Actual results will vary, especially with small numbers of trials.

Mutually Exclusive Events

Two events are mutually exclusive if they cannot both happen at the same time.

The addition rule for mutually exclusive events

If A and B cannot both occurP(A or B) = P(A) + P(B)

Example: rolling a die. P(1 or 2) = P(1) + P(2) = 1/6 + 1/6 = 2/6 = 1/3

Cannot roll a 1 and a 2 on the same throw → mutually exclusive.

Exhaustive events

A set of events is exhaustive if one of them must happen. The probabilities of an exhaustive set of mutually exclusive events sum to 1.

Example: rolling a dieP(1)+P(2)+P(3)+P(4)+P(5)+P(6) = 6×(1/6) = 1

Use this to find missing probabilities: if three mutually exclusive outcomes have P = 0.3, 0.45, and x, then x = 1 − 0.3 − 0.45 = 0.25.

Non-mutually exclusive events

If events CAN both happen, use the addition rule with the intersection subtracted (from Venn Diagrams):

P(A or B) — not mutually exclusiveP(A∪B) = P(A) + P(B) − P(A∩B)

Independent Events

Two events are independent if the outcome of one does not affect the outcome of the other.

The multiplication rule for independent events

If A and B are independentP(A and B) = P(A) × P(B)

Example: flipping a coin and rolling a die. P(heads and 4) = 1/2 × 1/6 = 1/12

The coin flip does not affect the die roll → independent.

Checking independence

Events A and B are independent if P(A∩B) = P(A) × P(B).

Example: P(A) = 0.4, P(B) = 0.3, P(A∩B) = 0.12. Check: 0.4 × 0.3 = 0.12 ✓ → independent.

Example: P(A) = 0.5, P(B) = 0.4, P(A∩B) = 0.25. Check: 0.5 × 0.4 = 0.20 ≠ 0.25 → NOT independent.

Repeated independent trials — Higher

P(event happens exactly k times in n trials)Use binomial approach: ⁿCₖ × pᵏ × (1−p)ⁿ⁻ᵏ

Example: P(exactly 2 heads in 3 flips) = ³C₂ × (1/2)² × (1/2)¹ = 3 × 1/4 × 1/2 = 3/8

Independent ≠ mutually exclusive. Mutually exclusive events cannot both happen (P(A∩B)=0). Independent events CAN both happen — knowing one occurred tells you nothing about the other.

Probability Calculator

Calculate theoretical probability, expected frequency, or check independence.

Probability Calculator

Choose a calculation type

Result
Select a calculation type and enter values.

Practice

Q1 — Theoretical probability

A bag contains 3 red, 5 blue and 2 green counters. What is P(blue)?

Q2 — Expected frequency

P(scoring a goal) = 0.4. A player takes 35 shots. How many goals are expected?

Q3 — Mutually exclusive

P(A) = 0.3, P(B) = 0.45. A and B are mutually exclusive. Find P(A or B).

Q4 — Independent events

P(A) = 0.6 and P(B) = 0.5. A and B are independent. Find P(A and B).

Exam Tips

01

Probability is always between 0 and 1

If your answer is greater than 1 or negative, you have made an error.

02

Complement: P(A') = 1 − P(A)

Often easier to calculate the probability of something NOT happening and subtract from 1.

03

Mutually exclusive: ADD probabilities

P(A or B) = P(A) + P(B) only when events cannot both happen.

04

Independent: MULTIPLY probabilities

P(A and B) = P(A) × P(B) only when events do not affect each other.

05

Experimental probability improves with more trials

A small experiment gives unreliable estimates. State this when commenting on results.

06

List outcomes systematically

Use a sample space table or ordered list. Missing outcomes is a common error.

07

Expected frequency is a prediction, not a guarantee

Write "expected" not "will". Probability gives long-run averages, not certainties.

08

Exhaustive mutually exclusive events sum to 1

Use this to find missing probabilities in a table or list.

Learning Objectives

Tick each off as you go.

Where this fits

Statistics — Foundation and Higher. Sampling, data collection and representation appear on both papers. Comparing distributions and critiquing statistical methods are common Higher questions worth 3–4 marks.

Sampling

A sample is a subset of the population selected for investigation. The goal is a representative sample that avoids bias.

Types of data

TypeDefinitionExamples
QualitativeNon-numerical categoriesColour, gender, favourite subject
Discrete quantitativeCountable whole numbersNumber of siblings, shoe size
Continuous quantitativeMeasured on a scale — any value in a rangeHeight, weight, temperature, time
Primary dataCollected directly by the researcherSurveys, experiments, interviews
Secondary dataAlready collected by someone elseCensus data, internet statistics

Sampling methods

MethodHow it worksPros / Cons
Random samplingEach member has equal chance of selectionFair, unbiased — needs numbered list
Systematic samplingSelect every nth member from ordered listSimple — could miss patterns
Stratified samplingSample in proportion to subgroup sizesRepresentative — more complex
Convenience samplingUse whoever is availableEasy — often biased
Quota samplingFill set quotas for each subgroupPractical — interviewer bias possible

Stratified sampling — calculations

Number from each stratum= (stratum size ÷ population size) × sample size

Example: School has 400 Year 10 and 600 Year 11 students. Sample of 50 needed.

Year 10: (400÷1000)×50 = 20   Year 11: (600÷1000)×50 = 30

Bias and questionnaire design

  • Biased question: "Don't you agree that exercise is good for you?" — leading question
  • Better: "How many times per week do you exercise?" — neutral, specific
  • Response boxes must cover all possibilities, be mutually exclusive, and not overlap
  • Pilot study: test the questionnaire on a small group before the main survey

Organising Data

Raw data is hard to interpret. Organising it into tables makes patterns visible.

Tally charts

Record data as it is collected. Five-bar gate method — every 5th tally crosses the previous four. Count in fives when reading.

Always check: sum of frequencies = total number of data items.

Grouped frequency tables — choosing class widths

  • Use equal class widths wherever possible
  • Aim for 5–8 classes — fewer loses detail, more makes patterns hard to see
  • Classes must be mutually exclusive: use 10 ≤ x < 20, not 10–20 and 20–30 (20 would be in both)
  • Classes must be exhaustive: every data value must fit in exactly one class
Never use overlapping classes. "10–20" and "20–30" both include 20. Use "10 ≤ x < 20" and "20 ≤ x < 30".

Two-way tables

Show two categorical variables simultaneously. Row and column totals must both equal the grand total. Use known totals to find missing values.

WalkBusCarTotal
Boys128525
Girls911525
Total21191050

Representing Data

Choosing the right chart for the data type is as important as drawing it accurately.

Choosing the right chart

Data typeBest chartKey rule
Discrete categoriesBar chart / pie chartGaps between bars; angle = proportion × 360°
Continuous groupedHistogram / frequency polygonNo gaps; plot midpoints for frequency polygon
Change over timeLine graph / time seriesJoin points; gradient = rate of change
Two variablesScatter graphLine of best fit; describe correlation
Raw data distributionStem and leafOrdered leaves; median and range easy to read

Histograms — Higher

Key formulaFrequency density = frequency ÷ class width

In a histogram the area of each bar represents the frequency, not the height. Bars have no gaps.

To find frequency from histogramFrequency = frequency density × class width
ClassFreqWidthFreq density
0 ≤ x < 1020102.0
10 ≤ x < 152555.0
15 ≤ x < 3030152.0

Cumulative frequency — Higher

A running total of frequencies. Plot upper class boundary against cumulative frequency, join with a smooth curve. Read off median (50th percentile), LQ (25th) and UQ (75th).

Interquartile range (IQR)IQR = UQ − LQ

Averages & Spread

Summary statistics reduce a dataset to a few key values describing centre and spread.

Measures of average (centre)

Meanx̄ = Σx ÷ n   or from table: Σ(fx) ÷ Σf
MedianMiddle value when ordered. Position = (n+1) ÷ 2
ModeMost frequent value. Can be more than one or none.

Measures of spread

RangeRange = max − min
Interquartile range (IQR)IQR = UQ − LQ   — not affected by outliers
Finding quartiles from ordered dataLQ = median of lower half   UQ = median of upper half

Example: 3, 5, 7, 8, 10, 12, 15, 18, 20. n=9. Median=10 (5th). LQ=6 (median of 3,5,7,8). UQ=16.5 (median of 12,15,18,20). IQR=16.5−6=10.5

Box plots (box and whisker diagrams)

Show the five-number summary: minimum, LQ, median, UQ, maximum.

Min LQ Median UQ Max

The box shows the middle 50% of data (IQR). Whiskers show the full range. Outliers may be plotted as separate points.

Comparing Distributions

Always compare both a measure of average (centre) AND a measure of spread. One sentence for each.

What to compare

CompareUseWhat it tells you
CentreMean or medianWhich group has higher/lower typical values
SpreadRange or IQRWhich group is more consistent/variable

Writing comparison statements

Always include: the statistic, the values for both groups, and a contextual interpretation.

Good comparison: "The median score for Group A (72) is higher than for Group B (65), suggesting Group A performed better overall. The IQR for Group A (18) is smaller than for Group B (24), meaning Group A's scores were more consistent."
Weak comparison (loses marks): "Group A did better." — no statistics quoted, no comparison of spread, no context.

When to use median vs mean

  • Use median when data is skewed or has outliers — it is not affected by extreme values
  • Use mean when data is fairly symmetric — it uses all values and is most sensitive to changes
  • Use IQR when comparing spread robustly — ignore extreme values
  • Use range when full spread matters — shows minimum and maximum

Practice

Q1 — Sampling

A school has 300 Year 10 and 200 Year 11 students. A stratified sample of 50 is needed. How many Year 10 students should be included?

Q2 — Histogram

A histogram bar for class 20≤x<30 has frequency density 3.5. What is the frequency?

Q3 — Comparing distributions

Group A: median = 72, IQR = 18. Group B: median = 65, IQR = 28. Which statement is correct?

Q4 — Questionnaire design

Which of these is a problem with the question: "How many hours of TV do you watch? □ 0–2 □ 2–4 □ 4–6"?

Exam Tips

01

Stratified sample: proportion must match population

(Stratum size ÷ total population) × sample size. Show this calculation in full.

02

Classes must not overlap

Use ≤ x < to ensure every value fits exactly one class. 10–20 and 20–30 is wrong because 20 fits both.

03

Histogram: area = frequency, not height

Frequency = frequency density × class width. Bars with different widths have different scales.

04

Always compare both centre AND spread

One mark for median comparison, one mark for IQR comparison. Never just say "Group A did better."

05

Quote the statistics in your comparison

Say "The median for A (72) is greater than for B (65)..." — values must appear in your answer.

06

IQR is more robust than range

IQR ignores outliers. Prefer IQR when comparing spread, especially if data is skewed.

07

Questionnaire: watch for leading questions and overlap

Neutral language, mutually exclusive classes, exhaustive options. No "sometimes/often" without definition.

08

Frequency polygon: midpoints, straight lines

Never use a curve. Plot at class midpoints, not boundaries.

Learning Objectives

Tick each off as you go.

Where this fits

Geometry and Measures — Foundation and Higher. Describing transformations precisely is essential — missing one detail loses the mark. Negative and fractional scale factors for enlargement are Higher only.

Reflection

A reflection flips a shape in a mirror line. Every point maps to an equal distance on the other side.

How to reflect

  • Each point maps to an equal perpendicular distance on the other side of the mirror line
  • The image is congruent to the original — same shape and size, mirror image
  • The mirror line is the perpendicular bisector of the line joining each point to its image

Common mirror lines

Mirror lineEffect on coordinates (x, y)
x-axis (y = 0)(x, y) → (x, −y)
y-axis (x = 0)(x, y) → (−x, y)
y = x(x, y) → (y, x)
y = −x(x, y) → (−y, −x)
y = a (horizontal)(x, y) → (x, 2a−y)
x = a (vertical)(x, y) → (2a−x, y)

Describing a reflection

Must state: (1) It is a reflection. (2) The equation of the mirror line.

Example: "Reflection in the line y = x"

Rotation

A rotation turns a shape about a fixed point (centre of rotation) through a given angle.

How to rotate

  • Every point moves through the same angle about the centre
  • The image is congruent to the original
  • Use tracing paper in the exam — trace the shape, pin the centre, rotate

Common rotations about the origin

RotationEffect on (x, y)
90° clockwise(x, y) → (y, −x)
90° anticlockwise(x, y) → (−y, x)
180° (either direction)(x, y) → (−x, −y)
270° clockwise = 90° anti(x, y) → (−y, x)

Describing a rotation

Must state: (1) It is a rotation. (2) Angle. (3) Direction (clockwise/anticlockwise). (4) Centre of rotation as a coordinate.

Example: "Rotation of 90° anticlockwise about (0, 0)"

Finding the centre of rotation

Draw lines joining each vertex to its image. The perpendicular bisectors of these lines intersect at the centre of rotation.

Translation

A translation slides a shape without rotating or reflecting it. Described using a column vector.

Column vectors

Vector (a above, b below)a = horizontal movement (+ right, − left)
b = vertical movement (+ up, − down)

Example: vector (3 above, −2 below) moves each point 3 right and 2 down.

Properties of translation

  • The image is congruent to the original — same shape, size and orientation
  • No rotation or reflection occurs
  • Every point moves by exactly the same vector

Describing a translation

Must state: (1) It is a translation. (2) The column vector.

Example: "Translation by vector (5 above, −3 below)"

The inverse translation uses the negative vector: if one way is (3, −2), going back is (−3, 2).

Enlargement

An enlargement changes the size of a shape while keeping angles the same. The shape and its image are similar.

Scale factor types

Scale factor kEffect
k > 1Larger image, same side as original relative to centre
0 < k < 1Smaller image, same side as original
k = 1No change (identity)
k < 0 (negative) — HigherImage on opposite side of centre, rotated 180°

How to enlarge from a centre

1

Draw rays from the centre through each vertex

These rays are your guide lines.

2

Multiply the distance from centre to each vertex by k

New distance = original distance × scale factor.

3

Mark new vertices and join them

All new sides are k times the original sides.

Describing an enlargement

Must state: (1) It is an enlargement. (2) Scale factor. (3) Centre of enlargement as a coordinate.

Example: "Enlargement with scale factor 3 centred at (1, 2)"

Finding the centre of enlargement

Draw lines from each vertex on the original to the corresponding vertex on the image. Extend them — they all meet at the centre of enlargement.

Combined Transformations

Two or more transformations applied in sequence. Order matters — the result of AB is generally different from BA.

Key facts

  • Reflection + reflection in parallel lines = translation
  • Reflection + reflection in intersecting lines = rotation
  • Two rotations about the same centre = single rotation (add angles)
  • Any combination of rotations and reflections = a single rotation or reflection (isometry)

Invariant points

A point that does not move under a transformation is called an invariant point.

  • Points on a mirror line are invariant under reflection
  • The centre of rotation is invariant under rotation
  • No points are invariant under translation (unless vector is zero)
  • The centre of enlargement is invariant under enlargement

Practice

Q1 — Reflection coordinates

Point A is at (3, 5). It is reflected in the x-axis. What are the new coordinates?

Q2 — Describing rotation

Which information is NOT needed to fully describe a rotation?

Q3 — Enlargement

A shape has area 12 cm². It is enlarged by scale factor 3. What is the area of the image?

Exam Tips

01

State the transformation type first

If you say "reflection" but give a rotation description, you get zero. Always name the transformation.

02

Rotation needs angle, direction AND centre

All three are required. Missing any one loses the mark.

03

Enlargement: area scales by k², volume by k³

Multiplying area by k (not k²) is the most common enlargement error.

04

Use tracing paper for rotations

You are allowed tracing paper in the exam. Use it for rotations and reflections in diagonal lines.

05

Translation: use column vector notation

Write the vector in column form. "3 right and 2 down" is acceptable but vector notation is cleaner.

06

Negative scale factor flips AND enlarges

Image is on the opposite side of the centre, rotated 180°. Only tested at Higher.

Learning Objectives

Tick each off as you go.

Estimation & Approximation

Round every value to 1 significant figure before calculating. This gives a quick check on whether your exact answer is reasonable.

Method

1

Round each number to 1 s.f.

38.4 → 40, 6.7 → 7, 0.048 → 0.05, 312 → 300

2

Calculate with the rounded values

Use simple mental arithmetic.

3

Write the estimate using ≈

Show all rounded values in your working — they earn marks.

Examples

Estimate 38.4 × 6.7≈ 40 × 7 = 280 (exact: 257.28)
Estimate (48.3 × 19.7) ÷ 3.8≈ (50 × 20) ÷ 4 = 1000 ÷ 4 = 250 (exact: 250.5)
Estimate √83≈ √81 = 9 (exact: 9.11)

Rounding

Two systems — decimal places (d.p.) and significant figures (s.f.). Know both.

Decimal places

Count digits after the decimal point. Look at the next digit: ≥5 round up, <5 leave unchanged.

3.7462 rounded to:1 d.p. → 3.7   2 d.p. → 3.75   3 d.p. → 3.746

Significant figures

Count from the first non-zero digit. Leading zeros are NOT significant.

3746.2 to:1 s.f. → 4000   2 s.f. → 3700   3 s.f. → 3750
0.004628 to:1 s.f. → 0.005   2 s.f. → 0.0046   3 s.f. → 0.00463
Trailing zeros matter. 3.70 (2 d.p.) is different from 3.7 (1 d.p.) — they show different levels of precision. Do not drop significant zeros.

Error Bounds — Upper and Lower Bounds

When a measurement is rounded, the true value lies within an interval. Finding the upper and lower bounds defines that interval.

Finding bounds

For a value rounded to n unitsLower bound = value − half a unit
Upper bound = value + half a unit

Example: a length is 7.4 cm (rounded to 1 d.p.). Half a unit = 0.05.

Lower bound = 7.4 − 0.05 = 7.35 cm

Upper bound = 7.4 + 0.05 = 7.45 cm

Written as: 7.35 ≤ length < 7.45 (note: upper bound is NOT included)

Bounds in calculations — Higher

OperationMaximum result usesMinimum result uses
a + bUpper(a) + Upper(b)Lower(a) + Lower(b)
a − bUpper(a) − Lower(b)Lower(a) − Upper(b)
a × bUpper(a) × Upper(b)Lower(a) × Lower(b)
a ÷ bUpper(a) ÷ Lower(b)Lower(a) ÷ Upper(b)
Subtracting to get maximum: use Upper − Lower (subtracting a smaller number gives a bigger result). This is the trickiest rule — remember it specifically.

Worked example — Higher

A rectangle has length 8.3 cm (1 d.p.) and width 4.7 cm (1 d.p.). Find the upper bound of the area.

Upper bound of length = 8.35, upper bound of width = 4.75Max area = 8.35 × 4.75 = 39.6625 cm²

Calculator Methods

Efficient calculator use avoids rounding errors and saves time.

Key calculator techniques

  • Brackets: always use brackets for complex numerators/denominators — (3+4)÷(2−1) not 3+4÷2−1
  • ANS key: use the previous answer in the next calculation without retyping
  • Memory (STO/RCL): store intermediate results to avoid rounding errors mid-calculation
  • Fraction mode: use the fraction key to get exact fractional answers
  • Standard form: use the ×10ˣ or EXP key — 3.2 × 10⁵ entered as 3.2 EXP 5

Avoiding rounding errors

Never round intermediate steps in a multi-step calculation. Only round the final answer.

Bad practiceStep 1: 3.14159 ≈ 3.14. Step 2: use 3.14. → introduces error
Good practiceStore full precision in memory. Only round the final answer to the required degree.

Checking answers

  • Always estimate before calculating — is your answer in the right ballpark?
  • Use inverse operations to check: if a ÷ b = c, verify c × b = a
  • Check units — area in cm², volume in cm³, speed in km/h
  • Check the answer makes sense in context — a human height of 170 cm is reasonable; 170 m is not

Practice

Q1 — Significant figures

Round 0.006247 to 2 significant figures.

Q2 — Lower bound

A mass is given as 5.6 kg, rounded to 1 decimal place. What is the lower bound?

Q3 — Bounds calculation

a = 12 (to nearest whole), b = 5 (to nearest whole). Find the maximum value of a − b.

Exam Tips

01

Show rounded values in estimation

Write each number rounded to 1 s.f. before calculating. Missing this step loses marks even if the estimate is correct.

02

Leading zeros are not significant

0.0062 has 2 sig figs (6 and 2). The zeros are placeholders.

03

Half the rounding unit for bounds

Rounded to nearest 10: half unit = 5. Rounded to 1 d.p.: half unit = 0.05. Always halve the precision unit.

04

Upper bound is NOT included

Write 7.35 ≤ x < 7.45 — the upper bound uses strict inequality.

05

Max of a−b: upper minus lower

Subtracting a smaller number gives a bigger result. Max(a−b) = UB(a) − LB(b).

06

Never round intermediate steps

Store full precision throughout a multi-step calculation. Round only the final answer.

Learning Objectives

Tick each off as you go.

Linear Equations

A linear equation has no powers higher than 1. Solve by performing the same operation to both sides until x is isolated.

Golden rule

Whatever you do to one side, do exactly the same to the other.

Types and worked examples

Simple: 3x + 5 = 203x = 15 → x = 5
With brackets: 2(3x − 4) = 166x − 8 = 16 → 6x = 24 → x = 4
Unknowns both sides: 5x − 3 = 2x + 93x = 12 → x = 4
Fractions: x/3 + 2 = 5x/3 = 3 → x = 9
Negative solution: 4 − 3x = 13−3x = 9 → x = −3

Setting up equations from context

Example: A rectangle has length (2x+3) and width (x−1). Perimeter = 28 cm. Find x.

Perimeter equation2(2x+3) + 2(x−1) = 28 → 4x+6+2x−2 = 28 → 6x+4=28 → 6x=24 → x = 4

Quadratic Equations

A quadratic has an x² term. Three methods — factorising (fastest), completing the square, and the quadratic formula (always works).

Method 1 — Factorising

Rearrange to ax² + bx + c = 0 first. Then factorise and set each bracket to zero.

x² + 5x + 6 = 0(x+2)(x+3) = 0 → x = −2 or x = −3
x² − 9 = 0 (difference of squares)(x+3)(x−3) = 0 → x = 3 or x = −3

Method 2 — Quadratic formula

For ax² + bx + c = 0x = (−b ± √(b²−4ac)) ÷ 2a

Example: 2x² + 3x − 5 = 0. a=2, b=3, c=−5.

Discriminant b²−4ac= 9 − 4(2)(−5) = 9 + 40 = 49. √49 = 7
Solutionsx = (−3+7)/4 = 1   or   x = (−3−7)/4 = −2.5

The discriminant — Higher

b² − 4acNumber of solutionsGraph
> 0Two distinct real rootsCrosses x-axis twice
= 0One repeated rootTouches x-axis once
< 0No real rootsDoes not cross x-axis

Simultaneous Equations

Two equations, two unknowns. Solve by elimination (add/subtract to remove one variable) or substitution.

Method 1 — Elimination

Make the coefficients of one variable equal, then add or subtract the equations.

Example: 3x + 2y = 13 and 2x + 2y = 10Subtract: (3x+2y) − (2x+2y) = 13−10 → x = 3
Substitute: 2(3)+2y=10 → 2y=4 → y=2
Solution: x=3, y=2
When coefficients differ — multiply first3x+2y=8 and 5x+3y=13
×3: 9x+6y=24   ×2: 10x+6y=26
Subtract: x=2, then y=1. Solution: x=2, y=1

Method 2 — Substitution

Rearrange one equation for one variable, substitute into the other.

y = 2x − 1 and 3x + y = 143x + (2x−1) = 14 → 5x=15 → x=3 → y=5. Solution: x=3, y=5

Substitution is essential when one equation is quadratic — Higher.

y = x + 1 and y = x² − 1 (Higher)x+1 = x²−1 → x²−x−2=0 → (x−2)(x+1)=0 → x=2,y=3 or x=−1,y=0

Inequalities

Solve like equations but keep the inequality sign. One key difference: multiplying or dividing by a negative number reverses the sign.

Linear inequalities

Solve 3x − 2 > 73x > 9 → x > 3
Solve −2x ≤ 6 — dividing by negative reverses signx ≥ −3
Double inequality: −1 ≤ 2x + 3 < 11Subtract 3: −4 ≤ 2x < 8 → Divide by 2: −2 ≤ x < 4

Number line representation

SymbolMeaningCircle on number line
< or >Strict inequality (not equal)Open circle ○
≤ or ≥Includes the boundary valueClosed circle ●
-2 0 4 -2 ≤ x < 4

Closed circle at −2 (included), open circle at 4 (not included)

Quadratic inequalities — Higher

Solve the equation first to find critical values, then sketch the parabola to determine which region satisfies the inequality.

x² − 5x + 6 > 0 → (x−2)(x−3) > 0Critical values: x=2 and x=3. Parabola is positive outside roots: x < 2 or x > 3
x² − 5x + 6 < 0Parabola is negative between roots: 2 < x < 3

Equation Solver

Solve linear and quadratic equations with full working shown.

Equation Solver

Linear (ax + b = c) or Quadratic (ax² + bx + c = 0)

Solution
Enter coefficients above.

Practice

Q1 — Linear equation

Solve 4x − 3 = 2x + 9

Q2 — Quadratic factorising

Solve x² + x − 12 = 0

Q3 — Inequality

Solve −3x + 2 > 14

Q4 — Simultaneous equations

Solve: 2x + y = 7 and x + y = 4

Exam Tips

01

Always rearrange to = 0 for quadratics

x² = 5x is NOT rearranged. Subtract 5x: x²−5x=0 → x(x−5)=0 → x=0 or x=5.

02

Dividing inequality by negative: reverse sign

−3x > 9 → x < −3. Forgetting to reverse is the most common inequality error.

03

Always check simultaneous equation solutions

Substitute both values back into BOTH equations. One equation is not enough.

04

Quadratic formula — always work out discriminant first

Calculate b²−4ac before doing anything else. It tells you how many solutions to expect.

05

Number line: open vs closed circles

Strict inequalities (< >) use open circles. ≤ ≥ use closed circles. Always draw the line.

06

Show all steps in equation solving

Method marks apply even when the final answer is wrong. Write each step on a new line.

Learning Objectives

Tick each off as you go.

Circle Theorems

Eight theorems — each must be stated by name when used as a reason in a proof.

The eight theorems

#TheoremKey fact
1Angle at centreAngle at centre = 2 × angle at circumference (same arc)
2Angle in semicircleAngle in a semicircle = 90° (diameter is the chord)
3Angles in same segmentAngles subtended by same arc are equal
4Cyclic quadrilateralOpposite angles sum to 180°
5Tangent-radiusTangent ⊥ radius at point of contact (90°)
6Two tangents from external pointEqual length; line to centre bisects angle between tangents
7Alternate segment theoremAngle between tangent and chord = angle in alternate segment
8Perpendicular from centre to chordBisects the chord (and the arc)

Applying theorems — method

1

Mark all given angles on the diagram

Write the values you know directly on the figure.

2

Identify which theorem applies

Look for the key features: diameter, tangent, cyclic quadrilateral, same arc.

3

State the theorem by name and calculate

Write "angle in semicircle = 90°" or "opposite angles of cyclic quad = 180°" as the reason.

Always give the theorem name as the reason. Writing "because it looks 90°" scores zero. Writing "angle in a semicircle = 90°" scores the mark.

Quick visual guide

Angle at centre = 2×circ

Theorem 1

90° Angle in semicircle

Theorem 2

Geometric Constructions

Use only a compass and ruler — no protractor. Leave all construction arcs visible for marks.

Key constructions

ConstructionMethod summary
Perpendicular bisector of ABOpen compass to >½AB. Draw arcs above and below from A and B. Join the two intersections.
Angle bisectorArc from vertex crosses both arms. Arcs from those intersections meet inside — join to vertex.
Perpendicular from point P to lineArc from P cuts line at two points. Perpendicular bisect that chord.
Perpendicular at point P on lineEqual arcs either side of P. Perpendicular bisect those two points.
60° angleDraw arc from vertex. Same radius arc from where it crosses the line — join.
Triangle given SSS/SAS/ASADraw base. Set compass to given length. Intersecting arcs give the third vertex.
Never rub out construction arcs. Examiners look for them as evidence of correct method. Losing arcs loses marks even if the final line is correct.

Loci

A locus is the set of all points satisfying a given condition. Always draw with a compass and ruler.

The four standard loci

ConditionLocusDrawn using
Fixed distance from a point PCircle, centre P, radius dCompass set to d
Fixed distance from a line ABTwo parallel lines distance d from AB (with semicircles at ends)Ruler + compass for ends
Equidistant from two points A and BPerpendicular bisector of ABPerpendicular bisector construction
Equidistant from two linesAngle bisector of the two linesAngle bisector construction

Combined loci — region problems

1

Draw each locus separately

Construct each boundary line or curve using the appropriate method.

2

Identify the required region

Shade the area that satisfies ALL conditions simultaneously.

3

Check boundary inclusion

"Less than" or "within" — boundary not included. "No more than" or "up to" — boundary included.

Example — treasure hunt problem

Treasure is within 5 m of point A, and closer to B than to C.

  • Draw circle radius 5 m centred on A
  • Draw perpendicular bisector of BC
  • Shade the region inside the circle and on the B-side of the bisector

Practice

Q1 — Circle theorem

A, B and C are points on a circle. Angle ABC = 38°. What is the angle at the centre subtended by arc AC?

Q2 — Locus

What is the locus of points equidistant from two points A and B?

Q3 — Cyclic quadrilateral

ABCD is a cyclic quadrilateral. Angle DAB = 112°. What is angle BCD?

Exam Tips

01

Name the theorem as the reason

"Angle in semicircle = 90°" scores the mark. "It looks right" does not.

02

Never erase construction arcs

Arcs are evidence of method. Leave every arc — even the "messy" ones.

03

Tangent meets radius at exactly 90°

Mark this angle on every circle diagram involving a tangent before doing anything else.

04

Cyclic quad: opposite angles sum to 180°

Not equal — they sum to 180°. The most commonly confused circle theorem.

05

Loci: always use compass and ruler

Freehand curves lose marks. A circle must be drawn with a compass.

06

Check boundary inclusion in region problems

"Within 3 m" — boundary not included (dashed). "Up to 3 m" — boundary included (solid).

Learning Objectives

Tick each off as you go.

y = mx + c

Every straight line graph can be written in this form. m is the gradient, c is the y-intercept.

The components

y = mx + cm = gradient (steepness — rise ÷ run)    c = y-intercept (where line crosses y-axis)
EquationGradient (m)y-intercept (c)
y = 3x + 23 (positive — slopes up)2
y = −2x + 5−2 (negative — slopes down)5
y = ½x − 3½ (gentle positive slope)−3
y = 40 (horizontal line)4
x = 3undefined (vertical line)none

Calculating gradient from a graph

Gradient = rise ÷ runChoose two clear points. m = (y₂ − y₁) ÷ (x₂ − x₁)

Example: points (1, 5) and (4, 11). m = (11−5) ÷ (4−1) = 6 ÷ 3 = 2

Use the widest possible points for accuracy — small triangles give rounding errors.

Rearranging to y = mx + c

Sometimes equations are given in other forms. Rearrange to identify m and c.

2y + 4x = 82y = −4x + 8 → y = −2x + 4   m=−2, c=4
3x − y = 5y = 3x − 5   m=3, c=−5

Parallel & Perpendicular Lines

Two lines are parallel if they have the same gradient. Perpendicular lines have gradients that multiply to −1.

Parallel lines

Parallel: same gradient, different y-intercepty = 3x + 2   and   y = 3x − 5   are parallel (both m=3)

A line parallel to y = 3x + 2 passing through (0, 7) has equation y = 3x + 7

Perpendicular lines — Higher

Perpendicular: gradients multiply to −1If m₁ = 3, then m₂ = −1/3 (negative reciprocal)
Rule: m₂ = −1 ÷ m₁m=2 → perp gradient = −½    m=−4 → perp gradient = ¼

Example: line perpendicular to y=2x+3 through point (4,1).

Perp gradient = −½. Use y−y₁ = m(x−x₁)y−1 = −½(x−4) → y = −½x + 3 → y = −½x + 3

Finding the Equation of a Line

Two methods — both reliable. Choose based on what information you are given.

Method 1 — From gradient and a point

y − y₁ = m(x − x₁)Substitute m, x₁ and y₁, then rearrange to y = mx + c

Example: gradient = 3, passes through (2, 7).

Substitutey − 7 = 3(x − 2) → y − 7 = 3x − 6 → y = 3x + 1

Method 2 — From two points

1

Find the gradient

m = (y₂ − y₁) ÷ (x₂ − x₁)

2

Use y − y₁ = m(x − x₁) with either point

Rearrange to y = mx + c form.

Example: points (1, 3) and (4, 12). m = (12−3)÷(4−1) = 3. Then: y−3 = 3(x−1) → y = 3x

Kinematic Graphs

Distance-time and velocity-time graphs are the two main types. Gradient is the key — it has a physical meaning in both.

Distance-time graphs

FeatureMeaning
Gradient of lineSpeed (distance ÷ time)
Steep lineFast speed
Gentle lineSlow speed
Horizontal lineStationary (not moving)
Line going downMoving back towards start
Curved sectionChanging speed (acceleration or deceleration)
Gradient = speed. To find speed: pick two clear points on the line and calculate rise ÷ run.

Velocity-time graphs

FeatureMeaning
Gradient of lineAcceleration (velocity ÷ time)
Positive gradientAccelerating
Negative gradientDecelerating
Horizontal lineConstant velocity
Area under graphDistance travelled
Area under v-t graph = distance. Split into triangles and rectangles to calculate the area.

Line Graph Plotter

Enter m and c to plot y = mx + c and see key features.

Straight Line Plotter

Enter gradient (m) and y-intercept (c)

Line properties
y = 2x + 1
Gradient: 2 (positive slope) y-intercept: (0, 1) x-intercept: (−0.5, 0)

Practice

Q1 — Gradient

What is the gradient of the line y = −3x + 7?

Q2 — Perpendicular gradient

A line has gradient 4. What is the gradient of a perpendicular line?

Q3 — Distance-time graph

A distance-time graph shows a horizontal line for 10 minutes. What does this mean?

Exam Tips

01

Rearrange to y=mx+c first

Always rearrange before reading off m and c. 2y=4x+6 → y=2x+3 → m=2, c=3.

02

Perpendicular: negative reciprocal

Flip the fraction and change the sign. m=⅔ → perp = −3/2.

03

Use large triangles for gradient

Bigger rise and run values reduce rounding error. Use the grid carefully.

04

Distance-time: gradient = speed

Steeper = faster. Horizontal = stopped. Downward slope = returning.

05

Velocity-time: area = distance

Split the area into triangles and rectangles. Do not confuse gradient (acceleration) with area (distance).

06

Check your equation works for given points

Always substitute the given point into your equation to verify it satisfies it.

Learning Objectives

Tick each off as you go.

Arithmetic (Linear) Sequences

Add the same number each time. The nth term is always of the form dn + c.

Finding the nth term

nth term = dn + cd = common difference   c = first term − d

Example: 5, 9, 13, 17…   d = 4.   c = 5 − 4 = 1.   nth term = 4n + 1

Example: 20, 17, 14, 11…   d = −3.   c = 20 − (−3) = 23.   nth term = −3n + 23

Is a value in the sequence?

Set nth term = the value. Solve for n. If n is a positive integer, it is in the sequence.

Is 85 in 4n+1?4n+1=85 → 4n=84 → n=21. Yes — 21st term.
Is 50 in 4n+1?4n+1=50 → 4n=49 → n=12.25. No — not a whole number.

Geometric Sequences

Multiply by the same ratio each time. The common ratio r is found by dividing any term by the previous term.

Identifying and working with geometric sequences

Common ratio r = T(n+1) ÷ T(n)2, 6, 18, 54…   r = 6÷2 = 3
nth termT(n) = a × rⁿ⁻¹ where a = first term

Example: first term 5, r = 2. nth term = 5 × 2ⁿ⁻¹

T(6) = 5 × 2⁵ = 5 × 32 = 160

Geometric sequences with r < 1

If 0 < r < 1, the terms decrease. Example: 80, 40, 20, 10…   r = ½. Terms halve each time.

If r is negative, terms alternate between positive and negative: 3, −6, 12, −24…   r = −2.

Special Sequences

These sequences appear by name in exam questions — know them all.

The special sequences

SequenceFirst termsnth term
Square numbers1, 4, 9, 16, 25…
Cube numbers1, 8, 27, 64, 125…
Triangular numbers1, 3, 6, 10, 15, 21…n(n+1)/2
Powers of 22, 4, 8, 16, 32…2ⁿ
Powers of 1010, 100, 1000…10ⁿ
Prime numbers2, 3, 5, 7, 11, 13…No simple formula
Fibonacci sequence1, 1, 2, 3, 5, 8, 13…Each term = sum of previous two

Triangular numbers

The nth triangular number = 1 + 2 + 3 + … + n = n(n+1)/2.

Example: 6th triangular number = 6×7÷2 = 21

Useful check: triangular numbers are always of the form n(n+1)/2. Is 45 triangular? n(n+1)/2 = 45 → n²+n−90=0 → n=9. Yes: 9×10÷2=45 ✓

Quadratic Sequences — Higher

The second differences are constant and non-zero. The nth term contains an n² term.

Method

1

Find second differences — must be constant

First differences, then differences of those. If constant, the sequence is quadratic.

2

a = second difference ÷ 2

This is the coefficient of n².

3

Subtract an² from each term

The remainders form a linear sequence. Find its nth term (dn+c).

4

Combine: nth term = an² + dn + c

Verify by substituting n=1,2,3 into your formula.

Worked example: 3, 8, 15, 24, 35…

1st differences: 5, 7, 9, 11   2nd differences: 2, 2, 2 → a = 2÷2 = 1

nTermTerm − n²
1312
2844
31596
424168

Remainders: 2, 4, 6, 8 → linear nth term = 2n. Full nth term = n² + 2n = n(n+2)

Check: n=3 → 3×5=15 ✓   n=5 → 5×7=35 ✓

Sequence Calculator

Enter the first four terms — get the nth term formula, check any term, and list the first 10.

Sequence Analyser

Enter the first four terms of your sequence

nth term
Enter four terms above.
Value

First 10 terms

Practice

Q1 — Arithmetic nth term

Find the nth term of: 7, 11, 15, 19…

Q2 — Geometric sequence

A geometric sequence has first term 5 and common ratio 3. What is the 5th term?

Q3 — Special sequence

What is the 8th triangular number?

Exam Tips

01

Verify nth term by substituting n=1,2,3

Always check your formula gives the correct first few terms before moving on.

02

Is it in the sequence? Solve and check for integer

Set nth term = value, solve for n. Only accept positive whole number answers.

03

Geometric: check ratio is constant throughout

Divide each term by the previous one. If the ratio is not constant, it is not geometric.

04

Quadratic: second differences must be constant

If first differences are not constant, find second differences. If those are constant, use the quadratic method.

05

Fibonacci: always add previous two terms

1,1,2,3,5,8,13,21,34… If asked to continue a Fibonacci-type sequence, add the previous two values.

06

Triangular numbers formula: n(n+1)÷2

Know this by heart — it comes up regularly and the formula is rarely given.

Learning Objectives

Tick each off as you go.

Pythagoras' Theorem

In a right-angled triangle: a² + b² = c² where c is the hypotenuse.

Finding the hypotenuse

c = √(a² + b²)a=6, b=8 → c = √(36+64) = √100 = 10

Common Pythagorean triples: 3-4-5, 5-12-13, 8-15-17, 7-24-25.

Finding a shorter side

a = √(c² − b²)c=13, b=5 → a = √(169−25) = √144 = 12

Distance between two coordinates

d = √((x₂-x₁)² + (y₂-y₁)²)(1,2) to (5,5) → √(16+9) = 5

SOHCAHTOA

Right-angled triangles only. Label H, O, A relative to the angle you are using.

The three ratios

SOHsin θ = Opposite ÷ Hypotenuse
CAHcos θ = Adjacent ÷ Hypotenuse
TOAtan θ = Opposite ÷ Adjacent

Finding a missing side

Hyp=10, angle=30°. Find Opposite.sin30°=O÷10 → O=10×sin30°=10×0.5=5
Adj=8, angle=40°. Find Hypotenuse.cos40°=8÷H → H=8÷cos40°=10.44

Finding a missing angle

Opp=5, Adj=12. Find angle.tanθ=5÷12 → θ=tan⁻¹(5/12)=22.6°
SOHCAHTOA only works in right-angled triangles. Use sine/cosine rule for other triangles.

Exact Trigonometric Values

Memorise these — they appear on non-calculator papers.

Exact values table

Anglesincostan
010
30°½√3/21/√3
45°1/√21/√21
60°√3/2½√3
90°10undefined

Memory pattern for sin

sin0°=√0/2, sin30°=√1/2, sin45°=√2/2, sin60°=√3/2, sin90°=√4/2

Numerators under the root: 0, 1, 2, 3, 4. Cos reverses this sequence.

Example: 4sin60° = 4 × √3/2 = 2√3

Sine Rule & Cosine Rule

For non-right-angled triangles. Sides a,b,c opposite angles A,B,C.

Sine Rule

Finding a side: a/sinA = b/sinB = c/sinCa=8, A=40°, B=65°. Find b.
b/sin65° = 8/sin40° → b = 8×sin65°/sin40° = 11.27

Use when: AAS or ASS (two angles and a side given).

Cosine Rule

Finding a side: a² = b² + c² − 2bc cosAb=7, c=9, A=50°. a²=49+81−2(7)(9)cos50°=49.2 → a=7.01
Finding an angle: cosA = (b²+c²−a²)÷2bc

Use when: SAS or SSS.

Area of any triangle

Area = ½ab sinCa=6, b=8, C=35°. Area = ½×6×8×sin35° = 13.76 cm²
Which rule? Right angle → SOHCAHTOA. AAS/ASS → Sine rule. SAS/SSS → Cosine rule.

3D Trigonometry

Identify a right-angled triangle within the 3D shape, extract it, then solve as 2D.

Method

1

Draw and label the 3D shape

Mark all given lengths and the unknown.

2

Identify and extract the right-angled triangle

Draw it separately as a 2D diagram.

3

Apply Pythagoras or SOHCAHTOA

You may need two steps — find a diagonal first.

Space diagonal of a cuboid

d = √(l² + w² + h²)3×4×5 cuboid: d = √(9+16+25) = √50 = 5√2 ≈ 7.07 cm

Angles of elevation and depression

  • Angle of elevation — measured upward from the horizontal
  • Angle of depression — measured downward from the horizontal
  • Both measured from horizontal, not vertical

Trig Calculator

Find missing sides and angles in right-angled triangles.

Trig Calculator

Right-angled triangles

Result
Select what to find and enter values.

Practice

Q1 — Pythagoras

A right-angled triangle has legs 6 cm and 8 cm. Find the hypotenuse.

Q2 — SOHCAHTOA

Adjacent=9 cm, angle=35°. Find the opposite side.

Q3 — Exact values

Find the exact value of sin60° × cos30°.

Exam Tips

01

Label H, O, A before choosing ratio

Mark sides relative to the angle you are using. Then SOHCAHTOA is obvious.

02

Pythagoras: square, add/subtract, root

Never just add sides. c²=a²+b² → c=√(a²+b²). Always take the square root.

03

Which rule for non-right triangles?

AAS/ASS → sine rule. SAS/SSS → cosine rule.

04

Exact values: sin pattern 0,1,2,3,4 under √

sin30°=√1/2=½, sin45°=√2/2, sin60°=√3/2. Cos reverses.

05

3D: extract the 2D triangle first

Draw it separately. Apply 2D methods to that triangle.

06

Check: hypotenuse must be longest side

And angles must be between 0° and 180°. Sanity-check every answer.

Learning Objectives

Tick each off as you go.

Standard Form

A × 10ⁿ where 1 ≤ A < 10 and n is an integer.

Converting to standard form

Large: positive power4,500,000 = 4.5 × 10⁶
Small: negative power0.000037 = 3.7 × 10⁻⁵

Calculations in standard form

Multiply: × A values, + powers(3×10⁴)×(2×10³) = 6×10⁷ → 6×10⁷
Divide: ÷ A values, − powers(8×10⁶)÷(4×10²) = 2×10⁴
Add/subtract: equalise powers first(3×10⁵)+(2×10⁴)=(3×10⁵)+(0.2×10⁵)=3.2×10⁵
If A goes outside 1–10, adjust. 15×10³ = 1.5×10⁴.

Standard Form Calculator

Standard Form Calculator

A₁ × 10^n₁

×10^

A₂ × 10^n₂

×10^
Result
Enter both numbers above.

Surds

An irrational square root. √2, √3, √5 are surds. √4=2 is not.

Simplifying surds

Find largest square factor√72 = √(36×2) = 6√2   √50=5√2   √108=6√3

Rules

√a × √b = √(ab)√3×√5=√15
√a ÷ √b = √(a/b)√20÷√5=√4=2
Adding like surds3√2+5√2=8√2   (unlike surds cannot be added)

Expanding

(2+√3)(4−√3)=8−2√3+4√3−3=5+2√3
(a+√b)(a−√b)=a²−b(2+√3)(2−√3)=4−3=1

Rationalising the denominator

1/√3 × √3/√3= √3/3 → √3/3
1/(2+√3) × (2−√3)/(2−√3)= (2−√3)/(4−3) = 2−√3

Exact Calculations

Leave answers as fractions, surds or π — do not round unless asked.

Examples of exact answers

Circle area r=5= π×25 = 25π cm²
Right triangle legs 1,1hyp = √2 → √2
4sin60°= 4×√3/2 = 2√3

Practice

Q1 — Standard form

Write 0.00045 in standard form.

Q2 — Simplify surd

Simplify √75.

Q3 — Standard form multiply

Calculate (4×10⁵) × (3×10⁴) in standard form.

Exam Tips

01

A must be between 1 and 10

25×10³ → rewrite as 2.5×10⁴. Always check.

02

Negative power = small number

10⁻⁴=0.0001. Not a negative number — a small positive one.

03

Surd: largest square factor first

√72: use 36, not 4. Largest factor gives simplest result in one step.

04

Rationalise: multiply by surd or conjugate

Get a rational denominator. For a+√b, multiply by a−√b.

05

Adding in standard form: same powers first

Convert both to same power of 10 before adding.

06

Exact answers: never round unless told to

Leave as 2√3 or 5π. Rounding loses marks when exact form is required.

Learning Objectives

Tick each off as you go.

Quadratic Graphs

y = ax² + bx + c is a parabola. a > 0 gives U-shape; a < 0 gives ∩-shape.

Key features

FeatureHow to find
y-interceptSet x=0 → y=c
RootsSet y=0, solve ax²+bx+c=0
Line of symmetryx = −b/(2a)
VertexSubstitute x=−b/(2a) to find y

Table of values — y = x² − 3x + 2

x−101234
y620026

Roots: x=1 and x=2. y-intercept: (0,2). Vertex: (1.5, −0.25).

Sketching Quadratics

Show key features without plotting every point.

Completing the square → vertex form

y = x²+6x+7= (x+3)²−9+7 = (x+3)²−2 → vertex (−3,−2)
y = a(x−h)²+kVertex at (h, k) — line of symmetry x=h

Sketching steps

1

Orientation — a>0 (U) or a<0 (∩)

2

y-intercept — set x=0

3

Roots — solve =0

4

Vertex — x=−b/2a then find y

Other Graph Types

Graph families — matching equations to shapes

TypeEquationKey features
Lineary=mx+cStraight line
Quadraticy=ax²+bx+cParabola
Cubicy=ax³+...S-shape
Reciprocaly=a/xTwo branches, asymptotes x=0, y=0
Exponential growthy=aˣ (a>1)Rapid increase, y-int (0,1)
Exponential decayy=aˣ (0<a<1)Decreasing, approaches y=0

Graph transformations — Higher

TransformationEffect on y=f(x)
y=f(x)+aTranslate up by a
y=f(x+a)Translate LEFT by a
y=af(x)Stretch vertically ×a
y=−f(x)Reflect in x-axis

Real-Life Graphs

Gradient and area in context

GraphGradient meansArea means
Distance-timeSpeed
Velocity-timeAccelerationDistance travelled
Cost vs quantityCost per unit

Curved real-life graphs

A curve = rate of change is not constant. Steep = rapid change. Flattening = slowing rate.

Gradient of tangent (Higher)Draw tangent at the point. Gradient = rise ÷ run of the tangent.

Quadratic Graph Plotter

Quadratic Plotter — y = ax² + bx + c

Key features
Enter a, b, c above.

Practice

Q1 — Roots

For y = x² − 4x + 3, what are the roots?

Q2 — Completing the square

Write y = x² + 8x + 7 in completed square form. State the vertex.

Q3 — Graph type

Which equation gives a reciprocal graph?

Exam Tips

01

Use a table of values for plotting

Calculate each term separately. One arithmetic error can distort the whole curve.

02

Join points with a smooth curve

Never use straight lines between quadratic points.

03

Roots: where graph crosses x-axis

Read carefully — use a ruler on the graph if needed.

04

Completing the square: halve b, subtract (b/2)²

y=x²+bx+c → (x+b/2)²−(b/2)²+c. Always subtract the square.

05

f(x+a) moves LEFT by a — not right

The direction is counterintuitive. f(x+3) shifts 3 units left.

06

Match graph to equation by features

Check orientation, y-intercept sign, number of roots and general shape.

Learning Objectives

Tick each off as you go.

Sample Spaces & Possibility Diagrams

Two-dice possibility diagram

+123456
1234567
2345678
3456789
45678910
567891011
6789101112
P(sum=7)6 outcomes highlighted → 6/36 = 1/6
P(sum>9)(4,6)(5,5)(5,6)(6,4)(6,5)(6,6) = 6 → 6/36 = 1/6
Total outcomes = n₁ × n₂. Two spinners with 4 and 5 sections → 20 total outcomes.

Tree Diagrams

The two rules

Multiply along branches (AND)P(A and B) = P(A) × P(B)
Add end results (OR)P(A or B) = sum of relevant end probabilities
Check: all end probabilities must sum to 1.

Worked example — biased coin, P(H)=0.6

Flip 1 → Flip 2 → Probability
H(0.6) → H(0.6) → HH: 0.36
H(0.6) → T(0.4) → HT: 0.24
T(0.4) → H(0.6) → TH: 0.24
T(0.4) → T(0.4) → TT: 0.16
Sum = 1.00 ✓
P(exactly one head)P(HT)+P(TH) = 0.24+0.24 = 0.48
P(at least one head)1−P(TT) = 1−0.16 = 0.84

Without replacement — Higher

Bag: 3 red, 5 blue. Draw two without replacement. P(both red)?

P(R then R)= 3/8 × 2/7 = 6/56 = 3/28

After drawing one red, only 2 red remain from 7 total — the second branch changes.

Conditional Probability — Higher

Definition

P(A|B) — probability of A given B has occurredP(A|B) = P(A∩B) ÷ P(B)

The denominator is P(B) — we restrict to outcomes where B has already happened.

Multiplication rule for dependent events

P(A∩B) = P(A) × P(B|A)Drawing 2 aces from 52 cards (no replacement):
4/52 × 3/51 = 12/2652 = 1/221

From a two-way table

60 girls (40 like sport), 40 boys (30 like sport). Total 100.

P(sport | girl)= 40/60 = 2/3 — denominator is girls only
P(girl | sport)= 40/70 = 4/7 — denominator is sport-lovers only

Practice

Q1 — Possibility diagram

Two fair dice rolled. How many outcomes have a sum of 8?

Q2 — Tree diagram

P(rain)=0.3. P(late|rain)=0.7, P(late|dry)=0.2. Find P(rain and late).

Q3 — Without replacement

Bag: 4 red, 6 blue balls. Two drawn without replacement. Find P(both red).

Exam Tips

01

Branches at each stage sum to 1

Check every fork. If they do not sum to 1, recheck your probabilities.

02

Multiply along, add across

AND = multiply along branches. OR = add the relevant end results.

03

Without replacement: update denominator

After removing one item, the total and count both reduce by 1.

04

All end probabilities sum to 1

Use this as a check. If they do not total 1, find the error.

05

Conditional: denominator is the given event

P(A|B) — denominator is P(B), not the whole sample space.

06

Possibility diagram: list systematically

Use a grid. Count outcomes by scanning rows and columns carefully.

Learning Objectives

Tick each off as you go.

Substituting into Formulae

Standard formulae

FormulaMeaning
v = u + atFinal velocity from initial, acceleration and time
s = ut + ½at²Displacement
D = M/VDensity from mass and volume
P = F/APressure from force and area
E = ½mv²Kinetic energy

Worked examples

v=u+at, u=5, a=−3, t=4v = 5+(−3)(4) = 5−12 = −7 m/s
E=½mv², m=2, v=6E = ½×2×36 = 36 J

Rearranging Formulae

Method — reverse BIDMAS

Make u the subject: v = u + atu = v − at
Make r the subject: A = πr²r² = A/π → r = √(A/π)
Subject appears twice — Higher: y = (x+3)/(x−1)y(x−1)=x+3 → yx−y=x+3 → yx−x=y+3 → x(y−1)=y+3 → x = (y+3)/(y−1)
Subject appears twice: collect all such terms, then factorise out the subject.

Equations, Formulae & Identities

The three types

TypeSymbolTrue when?Example
Equation=Specific values only2x+3=7 (x=2 only)
Formula=All valid valuesA=πr²
IdentityALL values of x3(x+2)≡3x+6

Proving an identity

Work on ONE side only. Never move terms across ≡.

Prove: (x+3)²−(x−1)² ≡ 8(x+1)LHS = (x²+6x+9)−(x²−2x+1) = 8x+8 = 8(x+1) = RHS ✓

Composite & Inverse Functions — Higher

Composite functions

fg(x) = f(g(x)) — apply g first, then ff(x)=2x+1, g(x)=x². fg(x)=f(x²)=2x²+1
gf(x) — apply f firstgf(x)=g(2x+1)=(2x+1)²=4x²+4x+1
fg ≠ gf in general. Order always matters.

Inverse functions

f(x)=3x−2. Find f⁻¹(x).y=3x−2 → y+2=3x → x=(y+2)/3 → f⁻¹(x)=(x+2)/3

Check: f(4)=10. f⁻¹(10)=12/3=4 ✓

Formula Calculator

Formula Substitution Calculator

Result
Select a formula and enter values.

Practice

Q1 — Substitution

Find E = ½mv² when m=4, v=3.

Q2 — Rearranging

Make r the subject of A = πr².

Q3 — Identity

Which is an identity?

Exam Tips

01

Bracket negative values

v=−3: write (−3)² not −3². The bracket prevents sign errors.

02

Rearrange in reverse BIDMAS order

Undo +/− first, then ×/÷, then powers/roots.

03

Subject appears twice: factorise

Collect all terms with new subject, then factorise it out.

04

Identity proof: one side only

Never move terms across ≡. Simplify one side until it matches the other.

05

Composite fg(x): g acts first

fg(x)=f(g(x)). The function nearest to x applies first.

06

Verify rearrangement with numbers

Substitute into original and rearranged form — both must give the same result.

Learning Objectives

Tick each off as you go.

Cumulative Frequency

Running total of frequencies. Plot against upper class boundaries. Join with a smooth S-curve.

Building the table

ClassFreqCumulative FreqPlot at
140≤h<15044150
150≤h<1601115160
160≤h<170924170
170≤h<180630180

Start the curve at (140, 0). Plot (150,4), (160,15), (170,24), (180,30). Join smoothly.

Reading from the curve (n=30)

MedianRead at n/2 = 15 → ≈160 cm
LQRead at n/4 = 7.5 → ≈154 cm
UQRead at 3n/4 = 22.5 → ≈167 cm
IQRUQ−LQ ≈ 167−154 = 13 cm
Plot at upper boundaries, not midpoints. Frequency polygons use midpoints. Cumulative frequency uses upper boundaries.

Box Plots

Five-number summary: Min, LQ, Median, UQ, Max.

Drawing a box plot

1

Draw a scaled number line

2

Mark Min, LQ, Median, UQ, Max

3

Draw box from LQ to UQ with median line inside

4

Draw whiskers from box to Min and Max

Interpreting

  • Box width = IQR (spread of middle 50%)
  • Skewed: median closer to LQ → positive skew; closer to UQ → negative skew
  • Outliers plotted as separate crosses beyond 1.5×IQR
Comparing two box plots: always quote median AND IQR for both groups.

Histograms

Area = frequency. Height = frequency density. Used when class widths differ.

Frequency density

DrawingFreq density = frequency ÷ class width
ReadingFrequency = freq density × class width
ClassFreqWidthFreq density
0≤x<1020102.0
10≤x<152555.0
15≤x<3030152.0

Bars 1 and 3 have the same height (2.0) but very different frequencies (20 vs 30) because of different widths.

Height ≠ frequency. Always multiply height × width to find frequency.

Time Series

Data at regular intervals. Identify trend and seasonal variation.

Key features

  • Trend — long-term direction (up, down, level)
  • Seasonal variation — repeating short-term pattern
  • Moving average — smooths seasonal variation to reveal trend

4-point moving average (quarterly)

Sales: 12, 15, 8, 10, 14, 17, 9, 11

MA₁=(12+15+8+10)/4=11.25   MA₂=(15+8+10+14)/4=11.75   MA₃=12.5...

Rising moving averages → upward trend despite seasonal fluctuations.

Scatter Graphs & Correlation

Correlation types

TypePatternExample
Strong positiveClose upwardHeight and weight
Weak positiveUpward, spreadAge and salary
Strong negativeClose downwardSpeed and journey time
No correlationRandom scatterShoe size and IQ

Line of best fit

  • Equal points above and below — use a ruler
  • Interpolate within data range only
  • Never extrapolate far beyond the data
Correlation ≠ causation.

Practice

Q1 — Cumulative frequency

n=80. At what cumulative frequency do you read to find the median?

Q2 — Histogram

Class 20≤x<25 has frequency density 6. What is the frequency?

Q3 — Box plot

Box plot: Min=10, LQ=20, Median=28, UQ=35, Max=50. What is the IQR?

Exam Tips

01

CF: plot at upper boundaries

Not midpoints. Start curve at (lower boundary of first class, 0).

02

Median at n/2, LQ at n/4, UQ at 3n/4

Use n not n+1 for CF graphs.

03

Histogram: area = frequency

Always multiply height × width. Never read height as frequency.

04

IQR = UQ − LQ

Not Max−Min. IQR = spread of middle 50%.

05

Compare distributions: quote both values

"Median A(72) > Median B(65)" and "IQR A(18) < IQR B(24)" — both needed.

06

Correlation ≠ causation

Never say one variable causes another from a scatter graph alone.

Learning Objectives

Tick each off as you go.

Compound Units

The three key compound measures

SpeedS = D ÷ T   (m/s, km/h, mph)
DensityD = M ÷ V   (g/cm³, kg/m³)
PressureP = F ÷ A   (N/m², Pa)

Converting compound units

m/s → km/h× 3.6   Example: 20 m/s = 20×3.6 = 72 km/h
km/h → m/s÷ 3.6   Example: 90 km/h = 90÷3.6 = 25 m/s
g/cm³ → kg/m³× 1000   Example: 5 g/cm³ = 5000 kg/m³

Why ×3.6? 1 m/s = 3600 m in one hour = 3.6 km/h.

Direct Proportion

Proportion types and equations

y ∝ xy = kx — doubling x doubles y
y ∝ x²y = kx² — doubling x quadruples y
y ∝ √xy = k√x — quadrupling x doubles y

Method — find k then solve

Example: y∝x². When x=3, y=36. Find y when x=5.

Step 1y=kx² → 36=k×9 → k=4
Step 2y=4×5²=4×25=100

Inverse Proportion

Inverse proportion equations

y ∝ 1/xy = k/x — xy = k (constant) — doubling x halves y
y ∝ 1/x²y = k/x² — doubling x quarters y

Example

y∝1/x. When x=4, y=15. Find y when x=12.

k=xy=4×15=60y=60/12=5

Identifying proportion type

When x doubles, y...Type
...doublesy ∝ x
...quadruplesy ∝ x²
...halvesy ∝ 1/x
...quartersy ∝ 1/x²

Growth & Decay

Compound interest / Growth

A = P × (1 + r/100)ⁿ£2000 at 4% for 5 years: 2000×1.04⁵ = £2433.31

Depreciation / Decay

A = P × (1 − r/100)ⁿ£18,000 car, 15%/year for 3 years: 18000×0.85³ = £11,054

Growth vs decay at a glance

TypeMultiplierExample
3% growth× 1.03Population, investment
3% decay× 0.97Depreciation, radioactive decay

Proportion & Growth Calculator

Units & Proportion Calculator

Result
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Practice

Q1 — Compound units

Convert 54 km/h to m/s.

Q2 — Direct proportion

y∝x². When x=2, y=20. Find y when x=5.

Q3 — Compound interest

£5000 at 3% compound interest for 4 years. Amount after 4 years?

Exam Tips

01

m/s → km/h: multiply by 3.6

km/h → m/s: divide by 3.6. The direction trips many students up.

02

Always find k from the given pair first

Substitute, solve for k, then use k to find the answer.

03

Check k is constant throughout

Direct: y÷x constant. Inverse: xy constant.

04

Compound interest ≠ simple interest

Use A=P×(multiplier)ⁿ. Never multiply P×r×n.

05

Growth >1, decay <1

3% growth → ×1.03. 3% decay → ×0.97.

06

Density triangle: D=M/V

Cover the unknown. M=D×V, V=M/D, D=M/V.